@ChrisWhite Brookhaven states they are both pure electron capture
@ChrisWhite my homework says the parent is pure electron capture and the daughter is a mixture
(yet Brookhaven lists 100% electron capture for the daughter, but gives energies for the Beta+ emitted)
user54412
2:36 AM
There does indeed appear to be conflicting information
user54412
Could be some poorly entered/formatted data in someone's database.
user54412
The other thing that comes to mind is that electron capture and beta+ emission are basically the same -- a nucleus susceptible to one is susceptible to the other. But EC depends on there actually being electrons. So if you fully ionize the atom, you can wait around for the rare positron, since nothing else can happen anyway.
@IceBoy this is the question :) I successfully showed the moment of intertia is that value....the problem is in my second part......let me explain :)
Since C is the center of mass....by symmetry....i drew it like this ....where in the first step I found the distance OC , and then I drew OC along a Line.....and since this will go like a circle, with radius OC....I thought the greatest $\omega$ would be at the lowest point....when taking conservation of energy :) and then I did :
You can also see the "zero PE line" I have drawn :) ....
Then I applied that the total potential energy turns to kinetic energy at the bottom which is :
Mgh at top changes to $\frac{1}{2} I \omega^2$ at the bottom.....I get a value for $w=12.8$ :
@IceBoy and I did the calculations from start about 3 times to make sure it's not an arithmetic error :) any idea what I have done wrong? :)
@TheArtist I think the problem is that you are using the moment of inertia about the center; you need to use the parallel axis theorem to compute the moment of inertia about C.
@GBeau - your second decay constant (the slower one) can be found by the asymptote of the combined decay curve (where the parent has essentially decayed completely so all decays you see are from the daughter) - just as the first is given by the initial slope
In applications where it is natural to use the angular frequency (i.e. where the frequency is expressed in terms of radians per second instead of rotations per second or Hertz) it is often useful to absorb a factor of 2π into the Planck constant. The resulting constant is called the reduced Planck constant or Dirac constant. It is equal to the Planck constant divided by 2π, and is denoted ħ (pronounced "h-bar") Source: Wikipedia. Note the hyphen between "h" and "bar"?
