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12:26 AM
Are there any physicians here? I have a doubt.
 
12:42 AM
34
Q: Stars and pins are retained when chat messages are moved!

UnihedronIn the chat system, stars and pins are retained when moved to another room. This is probably a bug. Here a picture: When a room owner pins a message, they can move it to another room, and they cannot unpin it. However when a starred message is moved to another room, the user can unstar it in t...

Ugh
 
@SirCumference Ancient bug, what bugs you about it now?
I can't recall we ever had a problem with that here, and it's easy enough to counter by the actual room owners
 
@ACuriousMind The fact SE doesn't care about the majority of bugs
 
12:58 AM
@SirCumference Well, they have to prioritize and generally, chat is rather low priority on their list compared to Q&A functionality
 
sup peeps
 
chillin u?
 
@0celo7 what is your doubt
@skullpetrol i'm chillin
 
1:27 AM
@Kenshin How does one get born with a crack and heroine addiction? What does it do?
How does a baby crave hard drugs?
 
this is because the mother used the drugs
and the baby has become dependent before birth
 
That I understand
 
these druigs pass through the placenta
 
But how does dependence manifest itself in infancy
 
what do you mean?
are you asking what are the signs and symptoms that a baby has?
 
1:43 AM
What in tarnation is a-goin' on in here?
 
2:03 AM
@Kenshin yeah
 
easily found on google
 
2:37 AM
@Kenshin I tried
Also I don't want illegal drugs in my search history 😳
 
vzn
@0celo7 ?!? why are you asking?
 
Hello
 
@0celo7 the symptoms are shown here: medlineplus.gov/ency/article/007313.htm
 
3:07 AM
@SirCumference Why do you think that?
Did you just make up that opinion based on the fact that there are unfixed bugs in existence, so you decided that must mean the SE team doesn't care?
 
3:25 AM
user image
2
Bye
 
 
1 hour later…
4:40 AM
@Kenshin You should stick with the word "dependence" rather than "addiction". The former is a physiological state, the latter a psychological one. (You can remain addicted after you are dried out, after all.)
 
4:54 AM
Good morning
 
5:17 AM
@dmckee I never used the word addiction?
 
5:30 AM
@Kenshin He just asked you to stick to "dependence" I guess. Never claimed that you used "addiction"..
 
6:08 AM
@Kaumudi.H Why you can't swear :-)
2
 
Can anybody help me in question number 4
According to me it should be option 3
 
@user123733 ok, so how heavy is 1/6 the mass of carbon
 
2g of hydrogen
 
ok, sure, thats actually for the mass of a mole of carbon but we had to get there anyways
lets call this new standard of mass the "gramme"
 
Ok
So it is 1 gramme
Oh no it should be option 4
Am I correct
 
6:21 AM
that should be the correct answer unless ive read it wrong
still kind of a bad question
 
Btw i got it
Thanks
 
yw
 
@anonymous I guess, but it's odd he thought he needed to tell me. I'm insulted that he thinks I didn't know the difference :p
 
@Kenshin Don't take it seriously. He sometimes does speak out of the blue :)!
@user123733 The answer is "remain unchanged". @Skyler Reason: If you take 1/6 then 1 amu will correspond to 2 amu. Therefore the number of particles will be Na/2 in one mole. When you multiply Na/2 × 2 amu (mass of 1 mole) you'll get Na × 1 amu only. So mass remains unchanged.
 
technically its the same amount of matter,
to answer this question fully:
your unit of mass has decreased relatively by a factor of two
this describes the same amount of matter
@anonymous thats why im saying this question sucks
it can be interpretted in a few ways
because lets say you now are describing matter in terms of "gramme", to make those units correspond to the number of atoms atoms you'd need twice as many atoms. So that is another reasonable answer a student would give and the teacher couldnt fault the student.
 
6:37 AM
@anonymous for which atom you are talking about
 
On transforming units the numerical value of mass might change but absolute value doesn't change. Yeah, the question is a bit faulty. I agree.
 
Yeah @anonymous on internet also there are different answers provided with different explanation
 
a far better way to ask this question is to say something like the atoms weigh half or twice as much . A mole can be defined as its number or as a relationship between number and mass.
 
So we can say option 1) is correct
 
technically number 1 is always true but a test may ding points off
its a REALLY stupid question
 
7:19 AM
1
Q: inactive users and Community revivals

anna vThis is an example , it was revived by Community . Could not Community acquire some intelligence? The user has been inactive since "Last seen Jun 2 '15 at 23:00" , All answers have a 0 vote count and two are later, I suppose from more revivals. I could think that an "and" combination of "ifs" ...

 
7:37 AM
@JohnRennie morning
 
@0celo7 Morning :-). Sorry for the high latency, I'm frantically kicking an obstinate server ... at the moment it's winning :-(
 
Good luck
I'm playing a game anyway
I should go to bed...
One more mission ;)
 
@0celo7 ;o
 
8:26 AM
@JohnRennie Are you being Served? ;-)
 
@skillpatrol I'm around, but still a bit busy with my servers for the next few minutes
 
We are doing a big database migration, and since I'm the only one who understands SQL Server I have to do the scary bits :-)
 
8:55 AM
but sql server is easy no?
 
@JohnRennie ooh scary bits!
 
@DanielSank as in frak this up and the company stops working and everyone will be staring at me
There's a reason I'm doing this on a Sunday morning!
 
@JohnRennie heheheh
You mean "bollocks it up"?
 
But it is basically done. All the performance checks have completed successfully. Basically now I wait for Monday morning to find out what I didn't think of :-)
 
9:17 AM
In every server room there is a glass panel on the wall with words Smash in case of emergency written above it.
Inside is a set of clean underwear.
 
9:28 AM
@JohnRennie why aren't there many tall buildings in london
 
Why? @Kenshin
 
cos it would look better with more scrapers
 
10:09 AM
> Few skyscrapers were built in London before the late 20th century, owing to restrictions on building heights originally imposed by the London Building Act of 1894, which followed the construction of the 14-storey Queen Anne's Mansions.
Though restrictions have long since been eased, strict regulations remain to preserve protected views, especially those of St Paul's, the Tower of London and Palace of Westminster, as well as to comply with the requirements of the Civil Aviation Authority.
This list of the tallest buildings and structures in London ranks skyscrapers and towers in London by their height. Since 2010, the tallest structure in London has been The Shard, which was topped out at 309.6 metres (1,016 ft), making it the tallest habitable building in Europe at the time. The second tallest is One Canada Square in Canary Wharf, which rises 235 metres (771 ft) and was completed in 1991. The third tallest is the Heron Tower in the City of London financial district, which was topped out in 2010 and stands at a height of 230 metres (755 ft), including its spire. The Greater London...
 
ty
 
"Due to the non-Abelian nature of the SU(2) and SU(3) groups, there are triple and quartic self-interactions "
Why does he say triple instead of cubic
What kind of madness is this
 
10:29 AM
-1
A: Effects of massive magnetic field generated by operation of the large hadron collider?

GRIITLOM32Unless we had a bunch of these types of machines around the globe, which we do. And they're used almost daily, oftentimes simultaneously, sometimes for months at a time. Each point is an attempt at manipulating the virtual particles that are the "black holes" of each point in space-time. CERN/GR...

is that answer "not an answer" flaggable?
or is it "very low quality" flaggable?
or is it allowed to stay?
"CERN/GRANSASSO/SLAC/FERMILAB ETC. ETC. ETC. are responsible for "climate change" (aka the coming pole shift)."
:D
"Each point is an attempt at manipulating the virtual particles that are the "black holes" of each point in space-time."
:DD
 
10:57 AM
@YashasSamaga Don't use flags for technical errors or wrong info....:P
Yes, it is definitely a non-sense answer
 
I already have got 3 flags declined an year ago for flagging answers with technical inaccuraices.
 
@YashasSamaga Complete gibberish, flagging as either NAA or VLQ would've been fine. That wasn't "wrong" so much as incomprehensible.
 
user228700
11:16 AM
Hello, everyone :-)
 
@Kaumudi.H hello :)
 
12:05 PM
@YashasSamaga Is the electric field due to a half cylinder at its axis $\frac{\sigma}{2\pi\epsilon}$ ? ($\sigma$ is surface charge density).
I derived it but somehow getting an extra factor of 2 in the denominator...
 
infinitly long?
 
Yes
 
you need the field inside?
or outside?
 
No, on axis
I divide it into wires
 
I am still thinking what kind of Gaussian surface to use
 
12:12 PM
Let us consider unit length of wire. $$\lambda=\frac{\sigma \pi r}{\pi}$$ right? $$\lambda$$ is charge per unit length of wire (which have negligible thickness).
 
what is that lambda?
 
Ok, we can't consider negligible thickness of wires I guess
 
where did a wire come from?
 
@YashasSamaga Cut the cylinder into infinite wires
Of infinitesimal width
Then we will integrate
 
oh
you aren't trying to find a Gausian surface?
your equation looked so nice
so I thought there was some Gaussian surface
 
12:15 PM
Gaussian surface...umm I will think of that later...
I'm trying the direct way first
 
the cylinder is of thickness zero
?
 
@YashasSamaga Yeah, I guess they have made that assumption...
 
even with that assumption you cannot break it into infinitely small wire
you will have a length of $Rd\theta$
*width of the wire
so the infinitely long wire formula won't work
 
@YashasSamaga $d\theta$ is infinitesimally small
I'm using calculus lingo
Okay!! Done :D
$$\frac{\sigma}{\pi\epsilon_o}$$
I forgot to take the cosine component initially
@YashasSamaga Most probably Gauss law won't help in this problem. I can't see any Gaussian surface which will simplify the problem.
 
@anonymous yea it shud work
my bad
 
12:26 PM
@YashasSamaga What should work? Gauss law?
 
I got confused with the case where there is a thickness and people assume the differential elements to be rectangles.
no the integration
I am not in form at all.
I should solve more problems.
 
Oh, here it isn't a good idea to consider rectangles...
Good luck :)
 
1:09 PM
@JohnRennie I'm getting a cassette deck
 
1:30 PM
@YashasSamaga Is there any shortcut to find average power from F-t graph? I have the force function as $F(t) = 1 N$ when $t \in[0 s,3 s]$ and $F(t) = (1-(t-3)/2) N$ when $t \in[3 s,5 s]$. I did it the long and dumb way by using $$P_{avg}=\frac{\int_0^3 F(t)v(t) dt + \int_3^5 F(t)v(t) dt}{\int_0^5 dt}$$. However, I think this method is too long. Any shortcuts you know of (geometrically perhaps or by using area under the graph) ?
 
The average is the area/total time
 
@YashasSamaga Remember that it is the F-t graph...
 
Mathematically, the arithmetic mean of a function is given by $$\frac{\int^a_b f(x)dx }{b-a}$$
ah
 
Yeah, i know that
But this is the F-t graph
 
P = Fv
 
1:32 PM
Area under the curve won't give anything useful
 
v = dx/dt
Area under the graph gives the impulse for F-t graph
 
Impulse is F.dt...yeah
How do you use it to find average power?
 
Did the particle start from rest?
nvm
 
Initially it has 2m/s
 
You can calculate the kinetic energy from momentum
 
1:33 PM
velocity
 
momentum change = impulse
 
So area is 3*1+(1/2)(2)(1)
 
$p_{final}$ - $p_{initial}$ = $\int F.dt$
 
=4
 
from $p_{final}$ you can get the new kinetic energy
it is a long process :/
 
1:35 PM
Lemme try
Initial momentum is 4 and final is 8 as the body has mass 2kg
now i need average power
so del KE first
 
yea
was it shorter?
 
Ah, yes $2.4 W$!
Yes definitely shorter
Thanks :)
 
2:00 PM
@BernardoMeurer retro!
I last used a cassette deck in around 1985 (a Nakamichi!!) and I don't miss them at all. Rubbish frequency response, rubbish dynamic range and they would tangle all the tape into the guts of the player at the least excuse.
Having said that, I've always wanted a reel to reel tape deck ...
 
huh
we have two anonymous?
 
@YashasSamaga i changed my name.. that is someone else
There was a havoc in the maths chat room
due to duplicate names
 
@anonymous ...what kind of name is "2017"? :P
 
2:13 PM
@ACuriousMind LOL :D I was thinking of something unique and funny :P
 
meh, 2017 is ok
 
I will update my name according to the year, every year :D
Until another duplicate 2017 appears :P
 
@anonymous so why didn't you use that unique funny thing for your name? :-)
 
@JohnRennie erm, how ? anon2017 ? :D I wished for a long time to keep a digit only name...that's why perhaps :P
 
I really liked the title of Murakami's 1Q84
 
2:16 PM
@anonymous what about the name 007?
 
@Kenshin Um, I could try it next month :)
 
ok cool
 
Time is up...I can't change the name for one month
 
that's in a few days
 
Nah, 30 days from now
 
2:17 PM
@anonymous I think John is as puzzled as I why you said that you thought of something "unique and funny"...and then chose the name of the current year instead of that. What's funny about the year?
 
Though I suppose there won't be another year 2017 so it is at least unique in that sense
 
Depends on the calendar you're using
 
also there is only one number with the combination 2017
 
@ACuriousMind Funny in the sense that is weird and I already managed to grab the attention of 4 people after the name change :)
BTW I just did it without thinking much
 
2017 is the unique number which can be written as a sum of 2016 and 1, in exactly two ways.
8
 
2:19 PM
-_-
 
@BalarkaSen :-)
 
That's also funny.
So there you go
 
2017 is a prime :D
 
Every number is unique and interesting.
It can be mathematically proven.
1 is interesting because if you multiply any number with 1, you get the same number.
 
sure, because the smallest uninteresting number would be interesting for being the smallest :P
 
2:21 PM
2 is the first prime
3 is the first odd prime
Assume that every number up to $x$ is interesting.
 
5 is the first prime not divisible by 2 or 3
 
so $x+1$ is the first non interesting number
the fact that it is the first non-interesting number makes it interesting?
so every number is interesting :D
 
4 is the first prime number that isn't prime
 
reductio ad absurdum ....my old friend :)
that isn't exactly maths but logic :)
Okay 2017 is a part of a Pythagorean triplet !
792,1855,2017
 
@YashasSamaga I saw it :)
The rules are cool!
 
I want to play!
 
I am busy :P
 
2:40 PM
@YashasSamaga, Hello
 
@Ramanujan Hi, what's the question?
 
@YashasSamaga., Weightlessness in free fall doesn't mean the acceleration due to gravity is zero, give reason
 
Weightlessness = normal force is zero
when there is nothing to provide a normal force
F = ma = mg
a = g
you accelerate at g
however, that is not the only case
the international space station is orbiting the earth at 400km
the gravitational force is providing the centripetal force to keep the space station in orbit
but the people on the space station feel weightless
 
@YashasSamaga,oo
@YashasSamaga, where are you from?
 
Karnataka
 
2:49 PM
@YashasSamaga, Are you a teacher?
 
:|
I don't know what to answer
I am both
student cum teacher
 
@YashasSamaga, in which level do you read?
 
IITJEE
and more
 
@YashasSamaga, do you have a Facebook I'd? I want to be friend with you. Please
 
I have a facebook id for namesake.
 
2:52 PM
@YashasSamaga, don't you use regularly?
 
I don't.
 
@YashasSamaga, any email ID?
 
I use email but I don't like to share my email id.
 
@YashasSamaga
, any specific reason
 
I don't like spam.
 
2:54 PM
@YashasSamaga, you can provide it to me!
 
@Ramanujan It's fine to ask other users for contact information, but once they have made it clear they don't want to give it out, you should respect that choice.
 
@ACuriousMind, ok. I am sorry for that.
 
@Ramanujan You can keep in touch with Yashas on this site...why is email or fb id necessary ?
 

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