« first day (1823 days earlier)      last day (3189 days later) » 
00:00 - 19:0019:00 - 22:00

12:19 AM
hahahaha
 
12:35 AM
@SohamChowdhury What book is that? I'd like to be able to tell people to avoid it.
 
@PVAL Pretty sure it is Algebra Ch0
 
Oh I already tell people to avoid that book.
 
Haha
 
It's a weird book.I sort of love it and hate it.
I hate it because it's ... hatable, but it also covers a lot of ground, quickly and well.
 
Care to elaborate, @PVAL? I have no opinion either way (actually I didn't mind the book), I'm just curious
 
12:41 AM
The past two answers I have written, I have ended up citing the same author. I sort of feel like a stalker.
 
Well I haven't looked at it for a long long time. IIRC it takes a lot of time developing categorical stuff with no good examples of categories present. Looking at it now, group actions are in the last 10 pages of the chapter on group theory.
2
Also I dont like the title
 
I agree.
 
Been doing much interesting @MikeMiller?
 
The point of introducing category theory early, in my mind, is to try to teach functorial thinking early. But functorial/categorical thinking (to the average mathematician) is mostly useful in places like algebraic topology when you're transporting structure between completely different contexts. There's not much of it in algebra. I liked Hungerford's book for this: occasionally there are proofs that are basically "This is unique because initial objects are unique"...
precisely when something like that shortens the proof and provides intuition, rather than for its own sake.
 
Oh it's useful to have, but it'll develop naturally anyway.
 
12:53 AM
@PaulPlummer: Just reading. I start TAing probability here in the summer session next week, but until then I can read in exotic locales. (I'm camping out at a friend's in a state park now.)
 
I think that is basically the approach Algebra Ch0 takes. Its not all categories, it just isn't afraid to go there. It goes fairly slow, for example it does not introduce functors till ch8 (I think...), which can be considered a good a bad thing, probably good from an educational perspective
Sounds fun, the reading in exotic locales.
 
Also why LA is nice. Can just go do work on the beach whenever.
 
@Mike, @PVAL: He does the usual $na = a + a + \cdots + a$ thing earlier on, though.
 
I have a tough time working in the heat, and the bright sun
 
I read some of Aluffi and don't really agree, @Paul. But I don't feel strongly enough to fight about it, just strongly enough not to teach out of it or suggest it to beginners.
 
12:58 AM
Well I don't think I would recommend Hungerford to beginners either :)
 
@SohamChowdhury: Sure, then this is inoffensive. Same proof, of course.
 
Oh, I guess he has an undergraduate book, never seen it, so not sure about that one.
 
But the initial object way shows that there is only one way to do it, as well, right? So there's that.
 
Never seen it either.
No, the other way does too. It's the same proof. This is just a cute way of phrasing it.
 
Haha, okay.
 
1:08 AM
@Paul: I tried to ask about you, but I guess the message didn't send. What are you up to?
 
@MikeMiller Not much, just moved, and will be starting graduate school soon. So I had to get ready for the move and do a bunch of stuff after the move (like fill out GA paper work etc). Attempting to study some algebra and topology, in hopes of passing a qual or 2 so that I don't have to take those classes. Today mostly procrastinated (did research for a math.se answer, listened to some podcasts, chatting...).
 
Those are fun. Where did you move to?
 
Oklahoma, will be going to University of Oklahoma (moving from Idaho)
 
Gotcha. What do you hope to study?
Fair warning: My computer claims to have 13 minutes of battery life left, so I'm going to vanish at some point.
 
Political science :) Nah, I am not 100% but they have some geometric group theorists, and what seems to be a good geometry and representation theory groups. So leaning towards GGT. @MikeMiller
 
1:16 AM
Seems like that's what you've been generally interested in before, yeah?
 
I've heard bad things about Oklahoma
Deep south :/
 
Its not deep south...
 
Oklahoma is at the tip of the midwest, and culturally tends to be more like the midwest than, say, Alabama.
 
Culturally it is probably more south than north (geographically it is basically the middle of the US)
 
1:19 AM
What I meant was: the more... nutty part of America.
Where they speak like Kletus
 
Right, Oklahoma is not so bad in that respect. You could do much worse.
 
Yah, for example Ted managed to escape Georgia with his life
 
Anyway good luck! I'm sure you'll be fine!
 
Hello!!
 
1:34 AM
I dunno I remain unconvinced about the cultural heritage of Oklahoma. To me it's more like Arkansas or Texas than Kansas. That outrageously racist chant that went viral was by an OU frat
 
Eh, maybe you're right, I didn't exactly do a cultural analysis of the place before moving. I am not sure how much you can base a place by its frats though.
 
its a good point. They represent a vocal but extreme minority even of young people
 
But football(ellipsoidishball) is pretty big here, so that is one indicator
 
I don't know much about the "dust bowl" region; I'm a born-and-bred rust-belter :P
I don't know if Oklahoma even qualifies as dust bowl, quite frankly!
 
Wayback Machine seems down. :(
 
1:45 AM
Well it is definetly dust bowl, pretty sure that is where The Grapes of Wrath was set
What did you want to wayback? @SohamChowdhury
 
1:59 AM
A blog post on a website that seems down.
 
rip
 
yup its down, been that way for less than an hour though
 
I have two minutes left. How exciting.
 
It feels like it has been longer than 13 mins
Were you forced to have the picture taken @SohamChowdhury It sort of looks like you are scared
 
Which picture?
Oh, god.
 
2:14 AM
Just the one on your account
 
Oh, no.
:P
 
 
5 hours later…
7:10 AM
hello - off topic. Why is it that when we want to check whether $S$ is a subring of $R$ the multiplicative property we have to check is that $ab\in S$ for $a,b\in S$ but with respect to the additive structure we check $a-b\in S$? Shouldn't the multiplicative property be $ab^{-1}\in S$ (for the same reason that showing $a+b\in S$ is not sufficient to show that $S$ is a subgroup of $R$?)
 
Rings do not nessesarily have multiplicative inverse. You're thinking of fields.
 
ah, of course, thanks
 
 
2 hours later…
Huy
9:05 AM
@DanielFischer: Do you know why in $S^n$ we have $R_{ijkl} = g_{ik} g_{jl} - g_{il} g_{jk}$? I have a computation of sectional curvature and it starts with this formula, but I've never seen it before. Is this a special case of the more general formula for $R_{ijk}^l$ expressed by Christoffel symbols which simplifies on $S^n$?
 
@Huy Sorry, but differential geometry is not something I'm comfortable with. Ted will probably know.
 
Huy
No problem, I'll ask him or Mike when they're around!
 
 
1 hour later…
10:29 AM
@Gato I think you might like to show the power for complex analysis here
15
Q: About the integral $\int_{-1}^1 \frac{1}{\pi^2+(2 \operatorname{arctanh}(x))^2} \, dx=\frac{1}{6} $

Chris's sis the artistHere is a question that naturally arose in the study of some specific integrals. I'm curious if for such integrals are known nice real analysis tools for calculating them (including here all possible sources in literature that are publicaly available). At some point I'll add my real analysis so...

@Gato specifically, the supplementary question.
 
@Chris'ssistheartist nice question
 
@Gato This is the way my book will look like. :-)
 
@Chris'ssistheartist very interesting, I am excited to read it :D
 
Click away the Wolfram message at the "x" next to the word sniply. The fluid flow animation graphics is amazing: haxiomic.github.io/GPU-Fluid-Experiments/html5
 
Hello, please when we have $\int_{\Omega}v_n(x)v(x) dx\rightarrow 0, \forall v\in W^{1,p}_0$ can we say that $v_n\rightarrow 0$ in $(W^{1,p}_0)^*$ ? please
 
10:32 AM
@Gato My opinion, it's just my opinion, the real analysis used very wisely is more powerful than complex analysis and offers far nicer and easier solutions.
 
@Chris'ssistheartist perhaps, but I will said that complex analysis doesn't require much knowledge, but real analysis tools, one needs lot of known facts.
 
I took all problems from Nahin's book, the ones considered the worst as difficulty and solved them all in very easy ways (from the complex analysis chapter).
 
@Chris'ssistheartist you second integral is much more difficult that the first one ^^
 
@Gato Yeap. :-) Both are created by me and many others like that far more complex.
What you see on MSE is a piece of cake (referring to my question on main) conpared to the hard stuff I have.
 
@robjohn Hello, please when we have $\int_{\Omega}v_n(x)v(x) dx\rightarrow 0, \forall v\in W^{1,p}_0$ can we say that $v_n\rightarrow 0$ in $(W^{1,p}_0)^*$ ? please
 
10:39 AM
compared
 
@Chris'ssistheartist there is lot of questions very hard here aout integrals
But to create it, it's very impressive :)
 
r9m
@Chris'ssistheartist Hello! How are you? :-)
 
10:56 AM
@Gato like, say, $$\int_{-\infty }^{\infty } \frac{e^{\pi x} \left(4 e^{\pi x} x+2 e^{\pi/2 x}\right)-\sqrt{e^{\pi x}} \left(\pi x^2+2 x+\pi \right) x}{\left(e^{\pi x}+1\right)^3 \left(x^2+1\right)^2} \, dx=\frac{5 }{32}\zeta (2)$$
@r9m hey! Not too bad. You? :-)
 
r9m
@Chris'ssistheartist alive :)
 
@r9m Good! Pretty silent in the last period of time though.
 
r9m
@Chris'ssistheartist ya! I was semi-depressed about a bunch of stuff .. that's all
 
@r9m Take some chocolate when depressed. :-)
(It works!!!)
 
r9m
@Chris'ssistheartist hehe! I do .. :) that's why I added the semi- ..
 
11:01 AM
@r9m I only hope you're not depressed with my stuff. I would feel guilty then. :D
 
r9m
@Chris'ssistheartist I usually get the depression from stuff external to mathematics .. :P math never depressed me :P
 
@r9m Is it about something bad?
 
r9m
@Chris'ssistheartist nah .. nothing bad.
 
@r9m You have too many positive qualities to ever let you caught by any kind of despression. Really.
Be honest with yourself and put the right price on you, those like you are very rare. ;)
 
r9m
@Chris'ssistheartist I'll keep that in mind, thanks!
 
 
1 hour later…
12:30 PM
@EricStucky
user image
2
I think that's brilliant.
 
Also I replied BTW
 
yeah I noticed :)
 
Glad your smiling now.
 
When you say you're running multiple computers, do you mean like hundreds?
 
12:35 PM
No, 6.
But they're rarely restarted so LOADS of tabs build up. So I'm in this chat from probably >20 different tabs.
 
But you can press the "leave room" button and that should just work?
per computer of course
 
Only in one chat. I'd have to leave it in everything I opened after the first time I joined
 
I'm not sure what you're saying
 
But ignorance may be bliss for you. I'm still going to be checking up on the chat even if I'm not there all the time.
 
There's a "leave that room" button to leave rooms remotely
 
12:37 PM
I'd have go to every tab I opened after the first time I joined and leave - the ones from before wont matter.
 
hmm that's interesting
Anyway I gotta get to teaching. I'll see you around.
 
Yes. Yes you will.
 
12:57 PM
@Balarka, of course I'm not learning tensor products now! I'm learning about linear maps. :)
 
@AlecTeal Nice one
 
Hello, @Rem.
 
Hello@Soham
Hey@Bal
 
I was outside all day.
 
Hey @Rememberme
 
12:59 PM
Hi
 
@Soham Sure, but you're a bit jumpy anyway. :P
 
Why@Soham .. In that rain what on earth are you doing outside
 
hi @Rememberme
 
Of course I am. I'm a hormonal 16-year-old, what do you expect? :P
 
haha
 
1:01 PM
You to be doing what the other 16 year olds do: fall in love with girls because they touched a part of you.
 
@AlecTeal did you take any codiene pal?
 
I only became amenable to learning lin alg when I learned that a module is just a vector space over any arbitrary ring. :)
 
@SohamChowdhury Isnt that the reason why modules were introduced
 
@skillpatrol why do you ask?
 
hi@EricStucky
 
1:02 PM
Being jumpy has grave consequences in mathematics. You'll turn into google.
 
@AlecTeal just wondering if you feel better.
 
Trust me, I know.
 
I went swimming yesterday and it has made my balls angry @skillpatrol - thanks for asking.
 
Personal experience?
 
1:04 PM
No, swimming.
 
yep
Hey, when are you going to meet up with SB? D'you have any idea?
 
Nope.
I should email him. Actually, I will, after I get groups down perfectly. :P
 
Can you guys secretly tell me who is SB?
 
My mentor.
 
Ah .. full name
 
1:06 PM
You wouldn't know him.
 
Where does he teach ISI?
 
is he a mathematician?
 
Okay dropping the topic
 
Algebraic topologist. And he doesn't teach in ISI, no.
 
Sometimes I don't know why I bother doing maths, my dream job is an Emerald Guard on Takeshi's castle.
 
1:07 PM
"Star farmer spotted!"
 
@Soham I am going to meet with a motivic guy after the exams. evilgrin
 
Should we be worried for his safety @BalarkaSen ?
 
what's a "motivic"?
 
You know that mod picture that Richard linked? It's a hammer with the word "mod" written on it
 
1:10 PM
motivation?
 
Did anyone else see it like this:
 
@AlecTeal yes
 
@BalarkaSen You mean all that AG stuff?
Sheesh, I am turning into Google. :'(
 
Today is one of those days when I think I'll leave mathematics after publishing my book. I don't know if I wanna reach a peak where to feel myself completely alone although being alone is not a problem to me, but it's about a certain math level that major part of math people would probably never enjoy. Then you share your stuff with yourself.
 
I shall find that mod pic and put them side by side "claim" and "reality"
 
1:11 PM
it's not exactly correct to say that motives are algebraic geometry, but whatever
 
@AlecTeal that's just the way some mods are pal
 
he's an A^1-homotopy theorist, in fact :)
 
Nooooooooo
I dunno what that is, but it sounds cool.
:P
Who turns you on to these people?
 
prof.
 
1:13 PM
he's in the faculty in the uni.
 
"Balarka, shon, tor khub htpy theory bhalo lage tai na? . . . " :P
Anyway, good luck.
 
i won't learn A^1-htpy theory from him. i just need a person i can pick up some etale-ish stuff.
hopefully, i would be able to exploit him rightly so as to know what a motive is too :P
 
@Chris'ssistheartist you'd be surprised how many smart people are out there...
 
Just wanna test something quickly:
Didn't work :/
 
@Chris'ssistheartist ...don't feel alone, yet.
 
1:17 PM
@skillpatrol It's not about smartness, it's more about much experience combined with crazy passion in a certain corner of math.
 
@Chris'ssistheartist that's what I meant too.
 
@skillpatrol ah, OK.
 
OMG! @N3buchadnezzar
 
Ramanujan would have never been what is known to be today without a crazy amount of work, driven by a burning passion.
 
1:21 PM
@N3buchadnezzar Look who's back :D
 
Yeah you compare yourself a lot to him @Chris'ssistheartist - don't others have to do that?
I've always said "It's not arrogance if your right" but you're just farming integrals right?
 
Party!!!
 
Looking for a sequence of functions such that $\lim_{n \to \infty} \int_0^1 f_n(x) \,\mathrm{d}x = 0$ but $f_n(x)$ is almost nowhere zero, eg $f_n(x) \to 0$ as $n\to \zero$ does not occur. any ideas?
 
Those hamsters are living my secondary dream.
 
Any ideas?
 
1:24 PM
@N3buchadnezzar
 
I think I got it, thanks!
 
@AlecTeal I can compare to anyone I want to, but that's not the point. Ramanujan is a referrence to me as performance, one that I wanna reach and exceed in the area of integrals, series and limits.
 
Good.
 
Maybe it's not the case if I leave mathematics after publishing my book.
 
Also that gif is brilliant, it could be the codeine talking but LOL so much
I mean it's a STOP sign!!
 
1:25 PM
x^n seems to work
 
In future @N3buchadnezzar post a question
 
he's too cool for that ;-)
 
@AlecTeal Random bits and bobs about mathematics is for the chat ;-) Also I have supreme seniority
2
 
@N3buchadnezzar Characteristic functions of intervals of length $2^{-k}$. Sweep the whole interval.
 
1:27 PM
Konig of coolness^
 
*König
@AlecTeal is that Pippi Longstocking?
 
No idea
 
Huy
1:46 PM
@N3buchadnezzar: What do you mean by almost nowhere zero? That it is almost everywhere nonzero?
That the set of points where it is zero has measure zero?
 
@Huy Look at the image i posted =)
 
Huy
There's a $^2$ in that image, but not in your original question.
Also, why is your image's quality so bad? :(
 
2:10 PM
@Huy Sorry about the image and the missprint... =(
Seems like a characheristic function might work as Daniel said.
 
Huy
@N3buchadnezzar: That was what I thought of first too, but you need to adjust it somehow.
Ah, what Daniel said should work actually.
 
@M.N.C.E. hey! Good approaches so far! :-)
 
@Huy Yeah. I get the idea, having small rectangles with width 1/2^k. Silly question is there a simple way to write that mathematically?
Something like $\Xi_{[0,2^-n]}(x) = 1$ ?
 
Huy
@N3buchadnezzar: I'm not sure what exactly you're trying to express with your equation.
Can you put into words what your aim is?
 
Express the characeristic function Danial described as an explicit formula
 
Huy
2:20 PM
@N3buchadnezzar: Can you express in words the exact properties you want that function to satisfy?
Or do you not know in general how to denote characteristic functions?
 
$$f_{2^k+r} = \chi_{[r\cdot 2^{-k}, (r+1)\cdot 2^{-k}]}$$
 
@Chris'ssistheartist Thanks. Unfortunately I haven't exactly figured out a solution to your other integral, but I will try again when I have the time.
 
@M.N.C.E. OK, no hurry with that, They are amongst the most beautiful integrals I managed to create this year, and I have versions far more complex but I only posted those $2$ versions. It's fascinating to see that the real analysis has a lot to say in this area :-)
 
2:36 PM
@Chris'ssistheartist: I finally decided to take a stab at your last integral. Just summing the residues in the upper half-plane works nicely.
 
@robjohn Back. Which one? The supplementary one in the last post?
 
@Chris'ssistheartist I think it was just the main one. I will look at the supplementary one.
 
@robjohn that was a fast one. :-)
 
@Chris'ssistheartist The answer involves a constant $A$. I am not sure what that is, but I probably haven't encountered it before. I will take a look later. I have a lot to do today, so I may not get back to stuff until tonight.
 
@robjohn Glaisher-Kinkelin constant
@robjohn OK
 
2:42 PM
@Chris'ssistheartist The long, but mechanical, part was computing the residues.
 
@robjohn Yeah.
 
Something I did a while ago. Good thing I was able to borrow a computer. :)
 
3:19 PM
@Guesswhoitis. I would go crazy without my computer.
Main is down >8( well, at least in read-only mode
 
Yes :-/ some server maintenance it appears.
Might I ask what happened with amWhy? I just noticed her reputation was set back to 1. I'm usually lurking on Math.SE without posting much
 
@StackStatus
Status updates for the Stack Exchange network, including http://t.co/VY1vdMiR. You can also find more detailed updates on http://t.co/uCcZjNx5.
489 tweets, 2.6k followers, following 1 users
@Clayton anyone who is suspended has their reputation reset to 1 temporarily.
 
That is what I thought; is it too much to ask what happened?
 
@Clayton The proper reputation is restored once the suspension is over.
@Clayton I can't say beyond what is publicly visible.
 
She always seemed really positive in all of the interactions I had with her (of course, the last year or so has had me very busy with research, so I haven't been on much)
Got it. Thanks!
 
3:26 PM
> This account is temporarily suspended for voting irregularities. The suspension period ends on Mar 21 '16 at 5:30.
 
Are you a professor @robjohn?
 
@Clayton I was, many years ago. Been doing some programming since then.
 
@robjohn Industrial/full-time programming or more for a hobby nowadays?
@robjohn I've been trying to get a grasp of Python, but I haven't had much luck. Project Euler has helped in forcing me to learn new techniques in programming.
 
@Clayton I worked at Apple for 8 years and now at UCLA for 18.
 
@robjohn I was going to post that answer, but I decided not to because the question was about real analysis techniques. I mention it in the comments under the question. But I still ended up using some complex analysis in my answer.
 
3:31 PM
@RandomVariable Ah, someone had said in a comment that the residue method didn't bear fruit, so I tried it and it turned out to be pretty low hanging.
 
@robjohn He was referring to the supplementary problem.
 
@RandomVariable Okay, so I misread.
 
3:44 PM
The site is back to normal.
 
@RandomVariable did you refer above in the comment to robjohn to a solution to the supplementary question from my post?
 
@Chris'ssistheartist yes
 
@robjohn Interesting.
 
@Chris'ssistheartist a comment about the supplementary problem.
 
@robjohn I was just curious to know if any did the supplementary one by any mean.
 
3:56 PM
@Chris'ssistheartist Oh, I don't know about that.
@Chris'ssistheartist I am working on it.
 
@robjohn My solution would shock you, btw (positively)! :D
 
@Chris'ssistheartist I have an interesting idea. Let me see if it works.
 
@robjohn OK :-)
 
@Chris'ssistheartist I haven't attempted the supplementary problem.
 
@RandomVariable OK
 
4:13 PM
@rob, consider yourself lucky that you're never without one. :)
 
Viewed 452 times in 2 days. :-)
(I could have had more upvotes in these circumstances :D)
 
I wonder if @anon is around.
 
why?
 
Oh, there you are. D'you know the Serre conjecture? It says that every projective module over polynomial ring is free.
 
nope
 
4:24 PM
What's the motivation behind this?
darn. thanks anyway.
I see words like "algebraic fiber bundles" flying around in google, thus the question.
 
4:37 PM
Projective modules are vector bundles. Every topological vector bundle over $\mathbb C^n$ is certainly trivial. Maybe every algebraic vector bundle over $\mathbb C^n$ is trivial, too.
Whence the question, which to my understanding is more fairly called a question than a conjecture.
 
Why is a projective module analogous to a vector bundle?
 
Serre-Swan
 
The defn is similar, I agree, but not every fiber bundle has the lifting property. (do vector bundles have those? I have no idea)
I have to google that.
 
What do you mean not every fiber bundle has the lifting property? A fiber bundle is a fibration. In any case, that's not the point being made.
 
The last time I heard, one can't lift maps in the base space to the total space in fiber bundles in general. I guess I am wrong?
 
4:51 PM
@MikeMiller How do you define an algebraic vector bundle?
 
@Chris'ssistheartist: do you mind if I add the Wikipedia link to your question?
 
@robjohn No, not at all. It's OK to me. :-)
 
@Chris'ssistheartist okay, done. I won't have time to look at the second question until much later.
 
@robjohn I don't see any change on wiki.
@robjohn I misunderstood your point. OK.
@robjohn btw, the second integral should proudly stay both on wiki and mathworld at Glaisher-Kinkelin constant description. :-)
 
5:19 PM
@Semiclassical Can we continue our discussion on quantum numbers?.. My exams are over so we can do the discussion if you are free.
 
you'll have to remind me what exactly we were discussing
 
How to derive n,l,m from SWE
 
ah, right
i'm not sure how far we got when we last discussed it, but the bottom line is that the 3D schroedinger equation is separable, first into radial v. angular parts and then the angular part into azimuthal and polar
 
okay
 
for a summary, take a look at this bit of wikipedia's page on the hydrogen atom: link
 
5:27 PM
okay lemme go through it
 
it's not explicitly stated in terms of separation of variables of a PDE, but that is the underlying math
for the explicit math, check out this part of Wiki's page on the Schrodinger equation, particularly the subsection on the hydrogen atom
 
I guess to understand it it would take me a few hours ....
Since I am not one of the brilliant ones
 
in essence, it's just separation of variables for PDEs. so i'd read up on that
 
I have done only till diffs .. I have never touched PDEs.. I will read up on that a bit I guess
 
r9m
5:54 PM
@mixedmath did you get my mail? :-)
 
@r9m It seems that mixedmath is not in the room. In general it is better to ask such things at Math Mods Office.
 
r9m
6:11 PM
@wythagoras thanks! :) :)
 
@r9m Maybe the best euphemism I read in the last period of time. :-)
 
r9m
@Chris'ssistheartist ???
 
Okay I have been asked to prove that Every compact subspace of a metric space is closed and bounded.

The proof that it is closed is very easy as every metric space is a hausdorff space ,and using definitions we can show that it is closed (Which I have done)

For bounded ,what I am thinking is that ,Since Y(lets us call the compact subspace as Y) is compact , there will be an open cover for the following subspace consisting of open sets from that metric space . In a metric space the open sets are open balls of given radius . Since the balls are of a given radius,the union of all these balls
 
@r9m Well, you did nothing wrong, but I felt some kind of smell for that "thanks! :) :)" above. :D
 
r9m
6:27 PM
@Chris'ssistheartist it was a genuine thanks -_-
 
@r9m OK :D
Out for a bit of jogging.
 
Hi @DanielFischer
 
6:45 PM
@DanielFischer This is simple, but would I be right in stating that the sets $S_{1} : \{ (x,y) \in \mathbb{N} \times \mathbb{N}: x \leq 2y \}$ and $S_{2} := \{ (x,y) \in \mathbb{N} \times \mathbb{N}: \frac{x}{y} \leq 2$ where $y \neq 0$ \} are not equivalent? Since $(0,0) \in S_{1}$ but not in $S_{2}$.
 
@Moses How do you define equivalence of sets in this context?
 
@TobiasKildetoft $S_{1} \subset S_{2}$ and $S_{2} \subset S_{1}$ iff $S_{1} = S_{2}$.
 
Hello@Tobias How are you?
Hey@Soham
 
@Moses Ahh, that is usually just called equality, not equivalence
@Rememberme Hi
@Moses And your reasoning is correct then
 
@Tobias Mind checking up a proof of mine .. ?
 
6:49 PM
@TobiasKildetoft Okay kewl, thanks.
 
@Rememberme sure
 
good night, @Rem.
 
good night @Soham
 
@Rememberme The idea is right, but the formulation is very messy
 
6:51 PM
Yes I guess I have to bring it into mathematical language
@Tobias I also had one more thing to ask you ...
Since you were not there all these days ... Do you know what homological algebra is all about . As in what do we do in that subject
I want to study it . It seems fun for some reason
Though I dont know anything about it
 
@Rememberme Yeah, I have a decent idea of the subject
 
Can you give me some briefing what it is about?
 
@Rememberme Originally, it started as a generalization of some concepts that emerges in algebraic topology, and then it took a life of its own
 
As in homology
 
right
the general idea if to start with something you want to study and then in a systematic way attach a chain complex to this object, which you can then take homology or cohomology of
 
6:56 PM
Oh.
 
usually one wants the 0'th (co)homology to be the original object (when this makes sense)
 
00:00 - 19:0019:00 - 22:00

« first day (1823 days earlier)      last day (3189 days later) »