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12:00 AM
@PedroTamaroff If your function is continuous and holomorphic in each variable separately, you get $f(z) = $ (product of Cauchy integrals for each variable). Continuity lets you write that as a single integral. Then $\prod_{i=1}^n \frac{1}{\zeta_1 -z_i}$ has a nice power series form, so swap sums and integrals to get a power series in $n$ variables for your function $f$.
 
You need to understand projective space ...
 
@MikeMiller!
How did the quals go?
 
You're supposed to be hiding, @Mike
 
@TedShifrin I heard several complex variables
 
Heard?
 
12:01 AM
Fine, @BalarkaSen
 
At this rate you guys will make me relearn Hörmander.
 
@TedShifrin OK, tabbed in and saw. I don't want to clean my room, which was next on the daily agenda.
 
@MikeMiller Is that a positive fine or a negative fine?
 
There's a negative fine?
I don't have results yet and won't for some time.
I guess being fined money is a negative fine. I don't like those.
 
You owe me dinner, @Mike. That's a negative fine :D
 
12:03 AM
SIGH
 
@PedroTamaroff One doesn't need continuity for the equivalence between "holomorphic in $n$ variables iff holomorphic in each variable separately", but apparently this is very hard. Hard enough that it's not covered in the $\Bbb C^n$ analysis book I'm reading. :P
 
@MikeMiller Ever heard of Goursat's theorem?
 
Osgood's Theorem, I think.
 
Wait there is no "easy" canonical way to define continuity on C^n?
 
@TedShifrin Osgood's is with the continuity assumption.
What??? @BalarkaSen
 
12:04 AM
@BalarkaSen We're talking about differentiability here.
 
Oh, rats. Well, it's been 41 years since I took SCV
 
So what's all the continuity about?
 
@PedroTamaroff uh, aye?
 
@MikeMiller I don't know what's going on anymore.
How did you do in Algebra?
 
@BalarkaSen If I have a continuous function on $\Bbb C^n$, that's holomorphic in each variable separately (i.e., $f(w_1, \dots, z_i, \dots, w_n)$ is a holomorphic function in the variable $z_i$ and the $w_j$ are constants), then it's a holomorphic function on $\Bbb C^n$ (can locally be described as a power series in $n$ variables).
yikes
 
12:06 AM
bleh
 
If I remove the continuity assumption, it's still true, but much, much harder to prove.
 
How do you even define holomorphicity without continuity
 
don't understand the question
@PedroTamaroff Results come back next week.
 
i am trying to remember if it's in Gunning/Rossi.
 
Oh you just need coordinatewise continuity.
 
12:08 AM
@BalarkaSen Right, but that doesn't imply continuity in general
 
Yes, yes, understood chief.
 
@TedShifrin Hartog's theorem? No, since I have it in my lap, and am glancing at a sentence that says they won't be covering that
 
I need to go sleep now.
 
Hartogs is also about removable singularities ... Super awesome
Night @Balarka
 
The theorem I'm thinking of is just the above, minus the continuity assumption
Don't know Hartogs other theorem; yet
 
@TedShifrin Remmert is starting to get interesting.
 
Holo extension across compact subsets
Sure, @Pedro
Not to mention problems in Polya-Szego :D
 
@TedShifrin Whoa... I asked someone earlier for an example of something that changes drastically between the single and multiple variable cases. There we have it.
 
Singularities have to be along codim-1 analytic subvarieties, @Mike
 
Nothing changes between single variable and multi there, does it? :P
 
12:14 AM
Well, more complicated when codim 1 isn't isolated points :)
 
Sure, things are gonna get more complicated. But Hartogs extension just isn't even close to being true - nor can I see a way to rewrite it to make it true - for $n=1$
 
No, of course, that's why it's awesome
 
Right!
 
Glad to make you happy
 
I'm making portabella sandwiches tonight, @TedShifrin
 
12:16 AM
This is going over my head. bored off. really going to sleep.
 
also, polydisk not biholo to disk in higher dimensions ... Super shocking :)
 
Portabella sandwiches need no background, @BalarkaSen
 
@TedShifrin what d'you mean by a polydisc?
 
@BalarkaSen Product of discs
 
Ah $D^n$
 
12:17 AM
$S^1$ is not a disc!
Admittedly I forgot to get buns... or tomatoes... so it looks like I'll be eating it on wheat bread with lettuce :P
 
Oh fine. $D$ then.
 
Is any one up there.. I had a confusion on a thing. Can I ask?
 
Ok, so $D^n$ is not conformal to $D$ for $n > 1$?
 
Its related to ratios.
 
@MikeMiller Yes, it does Mike.
 
12:19 AM
@BalarkaSen Your notation sucks!
2
 
AHAHAHAHAHAH
@MikeMiller Also ahem ahem Analysis is shith!
 
Let $\Delta(w;r_1, \dots, r_n)$ be $\{(z_1, \dots, z_n) \in \Bbb C^n : |z_i - w_i| < r_i\}$. This is the polydisc of polyradius $r$ centered at $w$.
 
What's the question @Swetank
 
Of course he never explicitly said analysis, just the subjects he never liked.
 
Let $B(w;r)$ be $\{(z \in \Bbb C^n : |z-w|<r\}$. This is the open ball of radius $r$ around a point $w$.
 
12:21 AM
@MikeMiller Whatevs. I got your point.
 
Then $\Delta(w_1;r_1)$ is not biholomorphically equivalent to $B(w_2;r_2)$.
 
@TedShifrin Find the ration of air density at A to the air density at B. What should i do A/B or B/A ?
 
First
 
@TedShifrin But the answer isn't matching :(
 
That's not my fault. :) Answers are often wrong :D
 
12:24 AM
Of course the answer is wrong @TedShifrin. It asked for ration, not ratio.
 
Good night, @Balarka
 
C'mon I was trying to make a pun.
 
@TedShifrin Agree .. But I had confirmed.. Answer isn't wrong.
@BalarkaSen What's that? I mean never heard of..
 
Dunno ...
 
Never you mind @Swetank.
OK, I am off.
 
12:26 AM
@BalarkaSen common, i am on it ..for 1/2 hour .. can't give up too soon.
@BalarkaSen my fault .. it will be ratio! :D
 
 
3 hours later…
3:30 AM
@PedroTamaroff, you should have. He loves Breaking Bad.
 
@KajHansen how do you get an Erdos number of 7/4?
Have someone with an Erdos number of 7 sit on the lap of someone with an Erdos number of 4 :-)
 
 
3 hours later…
7:02 AM
@Ice: I have an Erdos number of $\sqrt{14159265358979323}$ and a bacon number of $42i$
@IceBoy: A person with Erdos number of 7/4 would have to collaborate with someone with Erdos #1 for 3/4th of a project. Or it could also be obtained by chopping someone with Erdos #7 into 4 pieces but the former is more likely.
 
7:28 AM
@Nick are people with Erdos numbers allowed to multiply with each other, and if so what are the numbers of the off spring?
 
@IceBoy: Let's say guys with Erdos #3 and #4 have a kid. The kid can atmost have #3 or no Erdos number at all.
Idn't that reasonable?
@Ice: Btw, aren't you curious how I have such strange numbers?
I'll take your leaving to be a 'no'
 
Huy
8:04 AM
@BalarkaSen: I doubt you are old enough to watch Lord of the Rings already.
 
@Huy: He's read it.
 
Huy
@Nick: He doesn't read.
 
@Huy: Then, he watched the movies.
 
Huy
@Nick: That was my point.
 
@Huy: ok. Glad to know you've made your point.
 
Huy
8:08 AM
@Nick: I'm glad too.
@Nick: I don't know. I said something to BalarkaSen and you answered instead.
 
@Huy: To free ourselves from the vicious cycle of bored talking. Here's a question:
Find the angle marked as $x$
 
Huy
@Nick: If you're bored, help me out here: matheducators.stackexchange.com/questions/4438/…
 
@Huy: I'm never bored. I'm quite entertaining. Especially to myself :D
 
Huy
@Nick: Good.
 
@Huy: I think the concept of "playing with graphs" is a fundamental aspect of mathematics that most schools never teach.
 
Huy
8:22 AM
@Nick: What exactly do you mean by playing with graphs?
 
I mean to say most of your students can't graph most functions by hand and solve things by that method. But it may be too elementary to be taught after calculus.
Also, it isn't a small topic. It can fill a semester if every point is covered.
Here's the book:
I think it would make a nice course if coupled with concepts of calculus.
@Huy: But if that's too elementary. Then, how about basic Topology?
 
Greetings
@robjohn How does it look like?
 
Greetings
 
Hello
 
@Chris'ssis: Greetings :D Can you recommend a good course for @Huy to teach to highschoolers.
 
8:36 AM
I am curious @Nick :-/
 
@Nick I cannot do this, I have no background in mathematics, teaching ...
 
(removed)^2
 
@IceBoy: I know you are curious. So am I. What's your point?
 
@robjohn I think it's nicer to put it in this form
Compute $$\lim_{N\to\infty }\left( \frac{1}{2} \sum_{n=1}^{N} \frac{H_n^2 +H_n^{(2)}}{n}\sum_{k=1}^{n-1}\frac{(-1)^k}{ k} +\frac{\log(2)}{2} \sum_{n=1}^{N}\frac{H_n^2+ H_n^{(2)}}{n}\right) $$
 
Huy
@Nick: I'm a bit scared nobody would enrol in a topology course during high school, or too few people to make it happen.
 
8:44 AM
@Nick no point is pointless
 
@Huy: Well, I know not of topics that aren't too simple or too advanced to be taught of as a course in high-school. Now, there must be some Goldilocks topic out there.
@Huy: Um, what about conics. There's never a shortage of good things in that.
 
Huy
@Nick: Other teachers suggested conics to me as well. I just find them boring. .____.'
 
@Huy: It is. Even if you're Hank Green , conics would be boring.
 
Huy
Good to know. T__T
 
@Huy: mhh, maybe you could do extended trigonometry. Does your usual syllabus deal with hyperbolic functions? i think not.
 
Huy
8:53 AM
@Nick: Do you mean the sinh, cosh, etc? Then, yes, we deal with it in the standard curriculum.
 
Wow, that's a standard curriculum :D
 
Huy
@Nick: The thing is that I can only advertise my course with a short description, no pictures. So it has to be really interesting to people who are not crazy for maths already just by reading about it.
 
@Huy: ... Well, so I can't suggest Linear programming. lol
 
Huy
@Nick: What about linear programming? I don't know much about it. Can you explain why it could be appealing to high schoolers?
Need to catch my bus to uni. I'll be back to read it soon. :)
 
It's not. It's horrible. It's practical but it's horrible.
Linear programming (LP; also called linear optimization) is a method to achieve the best outcome (such as maximum profit or lowest cost) in a mathematical model whose requirements are represented by linear relationships. Linear programming is a special case of mathematical programming (mathematical optimization). More formally, linear programming is a technique for the optimization of a linear objective function, subject to linear equality and linear inequality constraints. Its feasible region is a convex polytope, which is a set defined as the intersection of finitely many half spaces, each of...
 
9:05 AM
@Huy High schoolers here do some linear programming in the 11th year. I think it's really fun, not hard.
 
It's just a kind of hyped up mathematical modelling that is very useful.
@Chris'ssis: It is fun. If you're taught it in the right way and you have questions that build up confidence.
@Huy: You have to be a really good teacher to make it as fun as you can for students.
 
@Nick I forgot this stuff, but I can tell I learned it alone. Of course, you need some practice, but that's all.
 
@Chris'ssis: Oh really? Then, could you refer me your textbook. I may have a slight aversion towards it.
 
Let me find a textbook and see if I can take some pictures.
 
I just need the title and author.
I can buy it from play store or bay it from mateys :D
 
9:12 AM
Hmm
 
Hmm.. or let me try MIT's open course ware. That should be helpful.
 
$$ \int_0^\pi \frac{\cos^2 x \,\mathrm{d}x}{1 + \cos x \sin x} = \int_0^\pi \frac{\cos^2 x \,\mathrm{d}x}{1 - \cos x \sin x} $$
Why ?
 
@Nick
 
@Huy: Or I suggest you do an extended course on linear algebra. A bunch of matrices, determinants and hey, you can can squeeze a lot of questions based on physics.
 
@rehband try this one (since you like the limits) :D $$\lim_{N\to\infty }\left( \frac{1}{2} \sum_{n=1}^{N} \frac{H_n^2 +H_n^{(2)}}{n}\sum_{k=1}^{n-1}\frac{(-1)^k}{ k} +\frac{\log(2)}{2} \sum_{n=1}^{N}\frac{H_n^2+ H_n^{(2)}}{n}\right)$$
 
9:17 AM
@Chris'ssis I can't believe how much you guys did in High School....we didn't do nearly that much here!
@Chris'ssis Ok, I'll try but it doesn't look do-able for me :) What does that (2) in the exponent mean?
 
@rehband $$H_n^{(2)}=\sum_{k=1}^{n} \frac{1}{k^2}$$
 
@Chris'ssis Ok, I see
Wow, what a limit lol
 
@rehband Its value is $$\operatorname{Li}_4\left(\frac{1}{2}\right)$$ ;)
 
@Chris'ssis Ok, haha I need to look up what Li_4 means
 
Some stuff like that I'll probably add to my book.
 
9:23 AM
@Chris'ssis People will be frightened
 
@rehband No, not at all.
 
So put it somewhere in the back :P
How did you find its value?
 
@rehband By personal research. ;)
 
@Chris'ssis That's awesome
 
@rehband I have a few limits like this one (all created in the last days). I might publish a book anytime, I have a lot of stuff.
Actually, I might publish more books, but I don't wanna hurry, I think I can come up with more and more amazing things.
Why should I hurry? I have no reason to do that.
 
9:33 AM
@Chris'ssis I believe you. I hope you publish a book sooner rather than later!
@Chris'ssis You're right of course, take as much time as you need, but I'm excited for it
 
@rehband For instance, you might do 100 limits and learn nothing new, but from this one you definitely learn something new. This is key of my book, each problem teaches you something new.
 
@Chris'ssis You mean the one you posted above?
 
@rehband Yeap.
 
That's great
How many problems do you want to include in your book btw. ?
 
@rehband At least 500 problems.
 
9:38 AM
That's far more than in Furdui's book, isn't it?
 
@rehband I don't know exactly how many books are there. Maybe around $300$?
 
Sounds about right
I really respect how you hard you're working for this. You seem to always be "on the grind"...I try to mimic that.
 
@rehband Thanks. Yeah, it's hard especially when you need to find alone all the energy you need to go further.
 
I changed my mind. I will see the psychologist and psychiatrist one last time and see what they say.
 
lol, every failed interview drains some of my energy ... :-))))
 
9:44 AM
@Chris'ssis Haha
 
@Chris'ssis I really think you should just become a mathematician. =)
 
The last time I was told I need a salary like the ones from NASA, and they cannot afford that. :-)))))))))
@WillHunting Yeap, I also think of that. :-)
 
I ordered the language books too fast. They mignt not be right for me. I will return them to amazon for a refund.
 
@rehband I do my best to get a job here. :-)
 
@WillHunting (+1)
 
9:47 AM
I am still thinking of the best book to learn foreign language.
 
@Chris'ssis Ok, fair enough :) I wish u the best of luck
 
If I don't become a mathematician, I don't know what I will do.
 
@WillHunting Did you start reading the books you bought?
 
@Chris'ssis No, like I said, my plan is to start next year. =)
 
@rehband Thanks :D
 
9:49 AM
@WillHunting You already have an undergrad. degree, right?
 
@rehband Yes. But I did not get first class honours, only a second class upper.
I have a question for the Americans.
 
@WillHunting What does second class upper mean?
 
Why do the American math graduate schools want you to know French, German or Russian? Why these three?
@rehband The class after first class, lol.
 
@WillHunting Ok :D
 
@rehband I did not do well mainly because of my mental problems.
 
9:53 AM
@WillHunting I'm sorry to hear. You've resolved those for the most part, right?
(We're all a little bit mentally ill imo)
 
@rehband Not really. But I hope to solve everything by the end of next year. I have not worked for seven years. =(
@rehband Yes, that is right.
Sorry to bore everyone for the millionth time.
 
@WillHunting =( Have you tried some type of treatment?
 
But I am still thinking of whether to use pgf or pstricks for latex graphics.
@rehband Yes, I have been taking meds for the last year but they don't help much. Last week, I started doing some psychotherapy, and I will go again next week.
And I am still thinking of whether to use living language series or teach yourself series for learning languages.
 
@WillHunting Hope psychotherapy is helping u
@WillHunting Flip a coin imo :P
 
It is as hard to choose language books as it is to choose math books.
But I will not change my math books again. The 12 holy math books is final. =)
 
10:01 AM
Great
 
@robjohn Are you here?
 
@WillHunting What is your book in homology ?
 
@Chris'ssis: Well, I translated much of that page. It wasn't as bad as when I was introduced to it. But MIT's content is a bit more nicer. But thank you btw.
 
@N3buchadnezzar If you ask me for a good book in algebraic topology, I will not recommend you any of my 12 holy books. My 12 holy books is for me to get a broad overview of everything, not a special book for a special topic.
 
@Khallil: How's your basic geometry?
 
10:04 AM
@Nick I say, forget about MIT OCW and just read your own books.
 
Basic geometry, @Nick?
 
@WillHunting I am
 
@N3buchadnezzar If you want a great book covering point set, algebraic and differential topology, go for Bredon's Topology and Geometry.
 
@WillHunting I maed a jok. You need a book on pudding.
 
10:05 AM
12 hours ago, by Balarka Sen
@TheGame I am Gandalf
 
Also first read meat
 
@robjohn I want to ask you this. Why do grad schools in US make us learn French, German or Russian? Why these three?
 
@WillHunting: ... that's good advice. I don't like it but I have to abide by it even if you didn't say to.
 
@N3buchadnezzar No meat, no pudding, lol.
 
French is pretty useful for reading texts in French as French mathematicians don't like writing in English, @Will.
 
10:06 AM
@robjohn Also, if French, German or Russian is important for math, why not learn all three? Why just one? It does not make much sense to me...
 
@WillHunting: Because atleast one of them will win.
 
thats the jok
 
yes, yes it was.
 
Ugh, what's the relationship between $\boldsymbol{r}(t)$ and $v$?
 
@Chris'ssis You like to break up a single sum into two pieces... like $\displaystyle\frac{\log(2)}{2}+\sum_{k=1}^{n-1}\frac{(-1)^k}{k}$
 
10:08 AM
$v = \Vert \boldsymbol{r}'(t)\Vert?$
 
What is r and what is v?
 
$\boldsymbol{r}$ represents a surface curve...and I believe $v$ is velocity - not too sure..
 
@Gustavo: what do you mean by surface curve?
 
@WillHunting I don't remember those being required, but for math, those seemed to be the most useful.
 
@robjohn Is that helpful?
 
10:09 AM
@robjohn They are required in most schools I checked out these days. =)
 
@Chris'ssis Not really, but it certainly makes the sum look more complicated
 
@Khallil: Yeah, like properties of parallel lines. Basic stuff.
 
Ok imagine a sphere in 3D. That is a surface. It's a 3-dimensional........manifold. Now, a surface curve is a curve around that sphere. Imagine getting a string and wrapping it around the sphere.
The path made by that string is called a surface curve. There are also plane curves that follow the same notion given a plane instead of a surface.
 
@robjohn Yeah, some ugly stuff ...
 
@GustavoMontano it's a 2-dimensional manifold embedded in $\mathbb{R}^3$
 
10:11 AM
That is correct. Robby my boy - my question was - what is the relationship between $\boldsymbol{r}(t)$ and $v$?
I actually don't know. $v = \Vert \boldsymbol{r}'(t)\Vert?$
 
I don't know what you're trying to imply by that, @Nick. I'm not studying the properties of parallel lines. :S
 
@Khallil: huh, here's a simple question for you:
Find $x$
 
It'll have to be quick.
I'm going out very soon.
"Image not found"
 
Hahahaha. That is a funny question :).
 
I'll check it out later. See ya!
 
10:14 AM
@GustavoMontano That depends on how $r$ is parametrized by $t$... if parametrized by arclength, then $v=1$ everywhere.
 
@Gustavo: What is the property of parallel lines that we use to solve that question called?
 
@robjohn. Is $v$ a scalar or vector?
DAMNIT
 
A mosquito is a vector.
 
A mountain climber is a scalar.
 
Nick is a good boy.
 
10:16 AM
@Gustavo: Don't believe me. I'm an idiot.
 
Haha, I'm pretty sure its a scalar....
 
:17917240
 
Or else $v$ is just a waste of notation.
 
Will Hunting is a fictional character potrayed by Matt Damon
Jasper Loy is the future recipient of the Field's Medal
 
@Nick 47
 
10:19 AM
@Nick Nick is, not Jasper Loy.
 
@GustavoMontano You have it written as a scalar, no?
 
@sarah Your avatar is still in the chat room, lol.
 
@robjohn: I know that. I need the name of the property you used.
 
@DanielFischer I would like to ask you what you think is the best book to learn German from on one's own.
 
@robjohn. Indeed I have. Great ^_^!
 
10:21 AM
@WillHunting how many languages do you know right now?
 
@WillHunting: Best way. Kidnap @rehband and tell him to teach it you.
 
@Moron Only two, lol.
 
Malay and English?
 
@WillHunting I have no idea. I didn't learn German from a book, everybody around me spoke German, so I kinda absorbed it.
 
@Moron English and Chinese, lol.
 
10:23 AM
@Nick I just added the changes in direction... they must sum to $0$ if the starting and ending directions are the same.
 
Chinese!!
 
Yes, my race is Chinese.
 
I comprehend 8 languages. English, Hindi, Malayalam, Tamil, Spanish, Klingon, Naavi and Math.
@WillHunting: Hope you win your race.
 
@DanielFischer I have finally decided to be reborn in Germany and not France.
 
@WillHunting are you winning the race?
 
10:25 AM
Both of you said the same thing!
 
@Nick And counting too...
 
@WillHunting Is that your decision? I thought Karma did that.
 
@Nick is there a Naavi dictionary?
 
@DanielFischer I think my decision will influence it a little.
 
@Moron: Actually I was right. Only 5 of them were real languages. My subconcious can't lie.
 
10:28 AM
Maybe. Anyway, @WillHunting, if you succeed, the next time after that, you will opt for France. Every [well, probably not every one] country looks better from the outside, you have to live through it to know what sucks how much there.
 
@robjohn: Probably. I just learnt it online.
 
@DanielFischer OK. But it certainly sucks where I am. The people here drove me mad.
 
@robjohn: Kaltxi' :D
 
@Nick Ah... I will have to take a look at the video. So the Naavi vocabulary consists of the words given in that video?
 
@robjohn In practice, do professors actually read papers in other languages?
 
10:33 AM
@WillHunting I had to read although I'm not a professor :-)
 
@Chris'ssis Well, you are a genius. =) I am only a banana.
 
lol, a banana? :-)
 
@robjohn: It consists of the words in the Avatar movie + words made Karyu Pawl. The video I linked is just a basic intro to a very big artificial language language.
 
Huy
@Nick: Thanks for the suggestions. What questions based on physics did you have in mind?
 
@WillHunting if they want the information in those papers, then yes.
 
10:35 AM
@Chris'ssis: He would be Dr. James Grimes if he could sing.
 
@WillHunting reading math in other languages, does not always require fluency in the language.
 
Huy
@WillHunting: Have you tried duolingo?
 
@WillHunting I was reading foreign papers even when I hardly understood something, out of curiosity, but now, when I work hard on my stuff, I also read some foreign papers whenever is needed. That happens pretty often.
 
@Huy Never heard of. I am not looking for websites, but books with audio. I have read many many reviews the past few days on different products but still cannot decide.
 
@Huy: Kinematics, rotational motion, waves, everything ends up with equations that need to be solved. Be imaginative. Math is more of a tool than just a bunch of universal thruths.
 
10:38 AM
@robjohn I think it is almost impossible to be fluent in a foreign language you only learn in your adulthood.
 
Huy
@Nick: I know it consists of equations that need to be solved. But they don't even know differential equations yet so I find it hard to explain it to them in a rigorous way.
 
@Nick Dr. James Grimes?
 
@Huy I don't know differential equations either, except separable variables, lol.
 
@Chris'ssis: Dr. James Grime. It was a typo. Lol, James W. Grimes was an American Politician :D
 
@WillHunting I used to know a couple of differential equations, then their solutions propagated...
 
Huy
10:40 AM
@WillHunting: I guess you don't do a lot if physics then.
 
@robjohn Your jokes are too sophisticated for me. I prefer stupid jokes. =)
 
@Nick Ah, never heard of him. :-)
 
@WillHunting I used to know a couple of differential equations, then they moved away.
@WillHunting is that better?
 
Russian is too hard! I need to learn another alphabet!
 
@Huy: Yes, but only basic diff. eq. It'll take 2 minutes to explain how to use them.
 
Huy
10:43 AM
@Nick: I don't think so. They don't know anything about integration and just a bit of differentiation. I want to teach it so they really understand what's going on and not that they just have a vague idea.
 
@WillHunting: I have to learn what is Aleph. ... What is Aleph?
@Huy: Well, I'm the worst person you can talk to. I am a vague idea.
lol
@Huy: How about Group Theory?
 
Huy
@Nick: How might that be appealing to high schoolers?
 
In mathematics and abstract algebra, group theory studies a type of algebraic structure called a group. Group theory is often used in mathematics as a starting point for the study of many algebraic structures, and of addition and multiplication of numbers. Because group theory is also useful for studying symmetry in nature and abstract systems, it has many applications in physics and chemistry. == Definition == A group is a set (collection) G whose members are called elements. The elements can be numbers of some kind, or other abstract objects. The elements can even be material objects. There is...
 
Huy
@Nick: I've only seen group theory in (linear) algebra, the point being vector spaces or Galois theory.
 
@Huy: It's a stepping stone to fun world of truer more abstract mathematics.
 
Huy
10:50 AM
@Nick: They won't enrol for a stepping stone, just for the real deal, imo.
 
@robjohn it's one of the most beautiful limits I've created this year. :-)
 
@Huy: Well, I believe you can market anything. Heck, take a class about fairly cutting cakes and kids will enroll if it offers them good grades.
 
Huy
@Nick: It's not graded.
 
@Huy: Oh, then you do need something interesting :O
 
Huy
@Nick: That's what I said. :D
 
10:53 AM
@Chris'ssis it's very nice. I will need to look at it more closely
 
Btw, cutting cakes and sandwiches can be a course:
380
Q: Splitting a sandwich and not feeling deceived

VividDThis is a problem that has haunted me for more than a decade. Not all the time - but from time to time, and always on windy or rainy days, it suddenly reappears in my mind, stares at me for half an hour to an hour, and then just grins at me, and whispers whole day: "You will never solve me..." P...

 
@robjohn thank you. OK! :-)
 
Huy
@Nick: I know, I've read that too.
 
@Nick do you suffer from many courses?
 
@robjohn: ... I don't suffer ... too much
 
10:56 AM
@Nick I don't suffer from mental illness... I enjoy every minute :-)
3
 
@robjohn: You have a mental illness?
 

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