Mathematics - 2012-09-09 (page 2 of 3)

2:07 PM

@JayeshBadwaik That will give you some issues with convergence and all.

I'd do $(a - 1 + (1 - a))$ or so.

Much fun.

@JonasTeuwen Yeah, I realized that later. Then I was thinking that @N3buchadnezzar has already proved that $f(ab) = f(a) + f(b)$ so then, we can use that to reduce the problem to the one which is within the range of convergence.

Jonas Teuwen

Splitting $0$ is always fun.

Jayesh Badwaik

@JonasTeuwen :-)

N3buchadnezzar

Hi!

Jayesh Badwaik

@N3buchadnezzar Going for dinner right now. BBL.

N3buchadnezzar

2:12 PM

@JayeshBadwaik Brb!

Jonas Teuwen

2:31 PM

New picture!

3

Nimza

Good day!

John Senior

2:49 PM

@Nimza Good day

Nimza

Hi, @JohnSenior

John Senior

looks like a quiet day in mathland :)

Nimza

aha

Jonas Teuwen

@JohnSenior Silence before the storm.

John Senior

@JonasTeuwen Oooh - are we expecting a storm?

Jonas Teuwen

2:57 PM

Dunno.

But usually when the come it has been... no storm before.

So! 1+1

John Senior

A storm might bring some excitement

Henning Makholm

@KannappanSampath Donald Duck? Looks unambiguously like Ludwig von Drake to me.

Jonas Teuwen

Actually I was getting paranoid as I thought he was mocking me with it!

Gustavo Bandeira

3:32 PM

The first time I've seen the Area 51 SE, I thought it had something to do with UFO's/Aliens.

2

Jayesh Badwaik

3:55 PM

@JonasTeuwen In your gravatar, you look really fat as compared to other pics.

Jonas Teuwen

@JayeshBadwaik Are you calling me fat bro?

Jayesh Badwaik

@JonasTeuwen No bro.

I am saying the pic is that way.

Jonas Teuwen

I was fatter there. I lose weight and gain periodically.

Jayesh Badwaik

Ohh.

robjohn

@JonasTeuwen sort of like variable rock stars...

Jonas Teuwen

4:03 PM

@robjohn Eh. Different reason.

Jayesh Badwaik

Talking of stars, I want this to happen soon.

Jayesh Badwaik

4:20 PM

The storm is coming in my city.

Peter Tamaroff

@robjohn Roooooooob

@JayeshBadwaik Run to the hills.

Gnintendo

4:36 PM

I wish we could include LaTeX graphs and whatnot in our answers :s

Jonas Teuwen

We can.

Gnintendo

waat

wuuuuuuuuuuut

I assumed we couldn't as I hadn't seen somebody use one yet

D;

Peter Tamaroff

@JonasTeuwen Jonesey.

@Gnintendo That's so silly.

Gnintendo

plus we only had the $$ operators and whatnot

:<

I think I'm being trolled >.>

robjohn

@PeterTamaroff yes?

Peter Tamaroff

4:45 PM

@robjohn I'm reading the proof that if $f$ is continuous and invertible, then $f^{-1}=g$ is continuous.

But I don't understand what Apostol is doing.

I kinda do, but not quite.

robjohn

@PeterTamaroff I don't have Apostol's book, so you'll have to provide some example.

Peter Tamaroff

@robjohn Yes, yes.

The hypotheis is that $f$ is strictly increasing and continuous. We proved $f^{-1}$ is strictly increasing.

To set things up, say $f$ is considered in $[a,b]$

Then $g$ is in $[c,d]$ with $f(c)=a$ and $f(d)=b$.

Now

Now, we have to prove that given any $\epsilon>0$ there is a $\delta>0$ such that, for all $y$, $g(y_0)-\epsilon<g(y)<g(y_0)+\epsilon$ whenever $y_0-\delta<y<y_0+\delta$

Apostol says this:

Let $x_0=g(y_0)$, so that $f(x_0)=y_0$. Let $\epsilon>0$ be given and let $\delta>0$ be the minimum of $f(x_0)-f(x_0-\epsilon)$ and $f(x_0+\epsilon)-f(x_0)$

Then this $\delta$ will work.

robjohn

That is all you need

Peter Tamaroff

@robjohn How?

Gustavo Bandeira

@Gnintendo Be careful with peter, his full name is Peter Trollaroff.

Jonas Teuwen

4:50 PM

@GustavoBandeira Stop insulting people, it is mean.

Peter is never trolling.

Peter Tamaroff

@JonasTeuwen Aww, thanks!

Jonas Teuwen

Yeah.

Gustavo Bandeira

NEVER TROLLING......

Jonas Teuwen

No caps please.

Damn, stores closed and NO FOOD.

Son of a crack.

robjohn

@PeterTamaroff $y_0=f(x_0)$ and $y_0-\delta\ge f(x_0-\epsilon)$ so $g(y_0-\delta)\ge x_0-\epsilon$

Peter Tamaroff

4:52 PM

@JonasTeuwen Go hunting.

Jonas Teuwen

For... rats?

Oh, right there are ducks, let me grab my gear.

Jayesh Badwaik

@JonasTeuwen Dude, its not later than 2000hrs in NL i guess.

Peter Tamaroff

@JonasTeuwen Ducks are tasteless. You'll need chutney.

You'll have to harvest, too.

Jayesh Badwaik

@PeterTamaroff Have you ever eaten a wild duck? It is damn tasty.

Jonas Teuwen

@JayeshBadwaik Yes, and a Sunday, this is a Catholic country.

Peter Tamaroff

4:54 PM

@JayeshBadwaik I was in Soviet Russia. Duck ate me.

Gustavo Bandeira

There's a coincidence: The book I'm reading (Barbeau's Polynomials) is from the year I was born.

Peter Tamaroff

@robjohn =)

Gustavo Bandeira

Barbeau wrote it for me. <3

user19161

@JonasTeuwen Unlike me. I am always trolling...

user19161

@GustavoBandeira So what is the book about? Polynomials only?

user19161

4:57 PM

@jonas Nice new picture!

user19161

@JayeshBadwaik You mean one that is cooked right?

Gustavo Bandeira

@WillHunting The book extends the high school curriculum and provides a backdrop for later study in calculus, modern algebra, numerical analysis, and complex variable theory. Exercises introduce many techniques and topics in the theory of equations, such as evolution and factorization of polynomials,

* solution of equations, interpolation, approximation, and congruences. The theory is not treated formally, but rather illustrated through examples. Over 300 problems drawn from journals, contests, and examinations test understanding, ingenuity, and skill. Each chapter ends with a list of hints; there are answers to many of the exercises and solutions to all of the problems. In addition, 69 "explorations" invite the reader to investigate research problems and related topics." *

Jayesh Badwaik

@WillHunting OFC.

robjohn

@PeterTamaroff similarly for the other side

Gustavo Bandeira

* In addition, 69 explorations...* XD XD XD

John Junior

5:00 PM

$\color{red}{\Huge\text{ >8(}}$

robjohn

@PeterTamaroff $y_0+\delta\le f(x_0+\epsilon)$ so $g(y_0+\delta)\le x_0+\epsilon$

user19161

@JohnJunior I see you are quite good at LaTeX too!

John Junior

@WillHunting So much left to learn...

Jonas Teuwen

LaTeX is pretty easy.

robjohn

@PeterTamaroff Does that make sense?

Peter Tamaroff

5:03 PM

@robjohn Let me read.

@robjohn I don't get it. Where are we using the continuity of $f$?

robjohn

@PeterTamaroff Can you find an inverse of a strictly monotone function that is not continuous?

user19161

@JonasTeuwen I see your website has been changing rapidly.

Peter Tamaroff

@robjohn Well, discontinuous stricticly monotone functions have ivnerses but they have places where they are not defined.

robjohn

@PeterTamaroff no, they are defined, but they are not strictly monotone

Peter Tamaroff

@robjohn OK, yes.

So?

robjohn

5:10 PM

@PeterTamaroff so the continuity is important only to show that the inverse is strictly monotone

Peter Tamaroff

@robjohn Mmmm... OK yes, but that is because the interval doesn't get partitioned.

robjohn

@PeterTamaroff sure. Is there a problem?

Peter Tamaroff

@robjohn I need to work it over.

robjohn

@PeterTamaroff think about it, it will make sense :-)

Peter Tamaroff

@robjohn I mean, by the contiunity of $f$ $$f(x_0)-f(x_0-\epsilon)$$ will be small, with small $\epsilon$.

Same for the other.

Now I need to turn that around to put it in terms of $g$

robjohn

5:14 PM

@PeterTamaroff But try to show $g$ is strictly increasing. Then the continuity of $f$ will play a part.

Peter Tamaroff

@robjohn Yes, I have shown that.

robjohn

@PeterTamaroff Then you have finished the whole thing, haven't you?

Peter Tamaroff

@robjohn I have only shown $g$ is strictly increasing. Now I need to show it is continuous.

John Senior

Hi all

anon

@JohnSenior Yo, are you familiar with Witt vectors?

John Senior

5:18 PM

@anon Not really - I know they are used in some ways with $p$-adics - but not got that far with them yet :(

John Junior

@robjohn Have you ever taught freshmen Calculus?

robjohn

@JohnJunior to classes of 300, yes

John Senior

@anon On the other hand, the W|P page on Witt vectors makes them seem pretty familiar ...

Peter Tamaroff

@robjohn OK, I have this

This $$g\left( {{y_0}} \right) - \varepsilon < g\left( y \right) < g\left( {{y_0}} \right) + \varepsilon $$

Is the same as

$${x_0} - \varepsilon < x < {x_0} + \varepsilon $$

Which is the same as

$$\tag 1 f\left( {{x_0} - \varepsilon } \right) < f\left( x \right) < f\left( {{x_0} + \varepsilon } \right)$$

Now I need to look at this

$${y_0} - \delta < y < {y_0} + \delta $$

And show it implies $(1)$

But that is the same as

$$f\left( {{x_0}} \right) - \delta < f\left( x \right) < f\left( {{x_0}} \right) + \delta $$

Now suppose the minimum is $$f\left( {{x_0}} \right) - f\left( {{x_0} - \varepsilon } \right)$$

Then

$$f\left( {{x_0} - \varepsilon } \right) < f\left( x \right) < f\left( {{x_0}} \right) + f\left( {{x_0}} \right) - f\left( {{x_0} - \varepsilon } \right)$$

But $$f\left( {{x_0}} \right) - f\left( {{x_0} - \varepsilon } \right) < f\left( {{x_0} + \varepsilon } \right) - f\left( {{x_0}} \right)$$

robjohn

@PeterTamaroff What?

Peter Tamaroff

5:24 PM

so

$$f\left( {{x_0} - \varepsilon } \right) < f\left( x \right) < f\left( {{x_0}} \right) + f\left( {{x_0}} \right) - f\left( {{x_0} - \varepsilon } \right) < f\left( {{x_0}} \right) + f\left( {{x_0} + \varepsilon } \right) - f\left( {{x_0}} \right) = f\left( {{x_0} + \varepsilon } \right)$$

And thus $$f\left( {{x_0} - \varepsilon } \right) < f\left( x \right) < f\left( {{x_0} + \varepsilon } \right)$$ as requiered.

@robjohn The minimum is the LHS.

@robjohn "Now suppose the minimum is"

robjohn

oh, I see you are doing one side is the max at a time

Peter Tamaroff

@robjohn the $\min$.

Jonas Teuwen

I wish to have a lovely estimate for...

$$\int_n^{n + 1} \mu(\{x : n + 1 > \phi(x) > r\}) \, \text{d}r.$$

Where $\phi$ is lsc on some topological space and $\mu$ is a probability measure 8-).

I need to get some measure of that thing out.

Think I must, think I cannot. Think I will. After duck hunt.

Why do I always read Zev Cojones?

John Junior

$\Huge\text{8-)}$

Peter Tamaroff

@JonasTeuwen LOL

Jonas Teuwen

5:29 PM

Seriously...

John Junior

Seriously not serious...

Jayesh Badwaik

Zev Cojones?

Mystic

5:46 PM

Can anyone explain the first solution given at math.stackexchange.com/questions/10616/…

I am not able to understand the step o(X^A Z)=P lcm(A,B)

John Senior

5:58 PM

@anon Are you working on $p$-adics or have you met Witt in commutative algebra?

John Junior

anon

@JohnSenior One of the topics I was presented involved using Witt vectors to characterize degree p^2 extensions of p-adic fields, so I am looking at Lenstra & Rabinoff's write-ups about them. I am also reorganizing the information into my own presentation.

John Junior

Interesting how sadness brings order to things @PeterTamaroff

Gustavo Bandeira

Off-Topic: This is a question for Jewelry SE. — Gustavo Bandeira 21 secs ago

John Senior

@anon OK - In that case you have got further with them than I have. I am trying to work out if I can get to understand class field theory without working through a whole book on commutative algebra (my weakest area)

Peter Tamaroff

6:02 PM

@GustavoBandeira That is unnecessary spam. Leave the LULZ for the chat.

Gustavo Bandeira

It's not spam.

anon

Did you bump that question just to make that joke?

Heh.

user19161

@PeterTamaroff It's LAWLZ, dude.

user19161

@JohnJunior That looks like Pedro!

John Junior

@WillHunting It is.

John Senior

6:06 PM

Does commenting bump a question? I am confused (not unusual!)

John Junior

Me too. I thought only editing bumps a question?

user19161

@JohnSenior It does not, but he might have bumped it otherwise as well.

Gustavo Bandeira

I just posted the comment.

user19161

@JohnJunior Only a question, answer, edit or bounty bumps it.

anon

Oh, nevermind, I thought comments bumped for some reason.

user19161

6:09 PM

@anon Is this your first day on SE? :-)

user19161

Oh dear, anon must be doing too much math. He has gone nuts.

3

first day, every day

lol

@WillHunting Thanks!

@anon last day, never

user19161

6:10 PM

Never too late.

user19161

Never say never. Justin Bieber.

anon

I was just about to ask why you didn't use the JB phrase.

John Junior

always say always?

user19161

My own creation: Justin Bieber. Just believe.

John Senior

@WillHunting who is Justin Bieber? (Serious question - I don't get out much)

Gustavo Bandeira

6:12 PM

@JohnJunior When should one say maybe then?

John Junior

never say always
always say never

Gustavo Bandeira

@JohnSenior Pop Singer

user19161

@JohnSenior He is a Canadian male pop singer who looks like a younger version of me. :-)

John Junior

@GustavoBandeira sometimes say maybe

Gustavo Bandeira

@WillHunting Male?!

Peter Tamaroff

6:14 PM

@WillHunting "GAAAAAAAAAAAAAAAY" - Seal

John Senior

@GustavoBandeira OK - thanks

John Junior

Justin Bieber

Justin Drew Bieber ( , born March 1, 1994) is a Canadian singer-songwriter, musician, producer, entrepreneur, investor, and actor. Bieber was discovered in 2008 by American talent manager Scooter Braun, who came across Bieber's videos on YouTube and later became his manager. Braun arranged for him to meet with entertainer Usher Raymond in Atlanta, Georgia, and Bieber was soon signed to Raymond Braun Media Group (RBMG), and then to an Island Records recording contract offered by record executive L.A. Reid. His debut extended play, the seven-track My World, was released in November 2009...

user19161

@PeterTamaroff Yes, I think I am ten per cent gay.

Jonas Teuwen

@WillHunting I think 11,7434905%

Peter Tamaroff

" singer-songwriter, musician,producer, entrepreneur, investor, and actor. " Well, that escalated quickly.

user19161

6:16 PM

@PeterTamaroff They forgot JL-lookalike.

John Junior

JL?

user19161

@JohnJunior Have you lost your memory of who I am?

John Junior

@WillHunting That is a question you must ask yourself...

user19161

@JohnJunior You should ask yourself too. :-)

John Junior

OK, who am I?

user19161

6:20 PM

You are SP. QED.

John Junior

Thank you.

JL

robjohn

@WillHunting you're the man of steel in disguise

John Senior

later all

user19161

@robjohn Oh, yes, the S too. :-)

user19161

@JohnSenior Laterz!

Matt

7:17 PM

@robjohn @anon On for a close and reopen action?

@JonasTeuwen

anon

Link it.

Matt

Link.

I take that to be a yes.

Need more people though.

anon

I have voted once and again.

Matt

Nicely done : )

robjohn

@anon I voted even though there was only one vote to reopen. I figured 2 or 3, it was going to get reopened.

Matt

7:21 PM

@anon Cheers!

Jonas Teuwen

Wow, he has quite some emo haircut!

Matt

L-8-R!

robjohn

Oh, if anon and Sasha voted to reopen, then I was the third. Good.

anon

@robjohn math.stackexchange.com/posts/193072/revisions

robjohn

@anon Okay. I thought someone said that Sasha voted. When I looked, there was just one vote, so someone must have voted before I performed the coup de grâce

anon

7:26 PM

Not only does the chatroom have a loose kill squad, we also have a loose resurrection squad.

Jonas Teuwen

I kill for fun. I don't even check who it is.

Confessions of a closer.

Khromonkey

can you help me with $1/a*1/(a-1)=1/a-1/(a-1)$?? thanks

i suck at inequalities

it must be pretty easy because someone just used it as it was obvious

guys could you help me out with this please?

Matt

7:42 PM

@anon @robjohn Can we do another close-reopen action?

@JonasTeuwen ^

@anon Having powerful friends feels good! : D

anon

@Khromonkey That's not an inequality, it is partial fraction decomposition (that particular one I have used fairly often as an obvious fact). Try going from the right side to the left side by putting both fractions under a common denominator. (That is, multiply the first by (a-1)/(a-1), and the second by a/a.)

Matt

Call 4 votes.

@robjohn Thank you : ) Nice.

robjohn

@Matt I did a summary reopen since I figured it would happen anyway.

Jayesh Badwaik

@robjohn What is the stuff with closing and reopening posts? Does it have to do with clearing the pending close votes or something similar?

anon

By "what is the stuff with," are you asking "what is the motivation for"?

robjohn

7:50 PM

@JayeshBadwaik that's it. It just clears the pending close votes.

Jayesh Badwaik

@anon Yup, the motivation.

robjohn

@Khromonkey $\displaystyle\frac1{a-1}-\frac1a=\frac{a}{a(a-1)}-\frac{a-1}{a(a-1)}=\frac1{a(a-1)}$

Jonas Teuwen

@Matt Have you seen my picturrrre?

I removed the beard.

Khromonkey

got it thanks @robjohn and@anon

MeAndMath

Hi Guys!!!!

Gustavo Bandeira

7:58 PM

Yo!

MeAndMath

@GustavoBandeira How r u?

Gustavo Bandeira

Fine, u?

MeAndMath

@GustavoBandeira good,thanks.

will u mock me today?

Gustavo Bandeira

Mock?

I don't mock people.

MeAndMath

yes.zuar,zombar...

Gustavo Bandeira

8:06 PM

I never did that. :-(

Tô numa bienal do livro aqui em Garanhuns.

A piada: todos os livros são lacrados.

Peter Tamaroff

@GustavoBandeira PORTUGUESLIÑO

Gustavo Bandeira

You're doing PORTUCYBERBULLYING, dude....

2

PORTUCYBERBULLYINGCYBERXENOPHOBY

Peter Tamaroff

@GustavoBandeira Dude, fuck off. Why?

Wait. Pebbles.

Matt

@JonasTeuwen Yes, saw. The star there is from me.

Peter Tamaroff

@Matt Matt.

Isn't this wrong? Viz, "summing infinity terms"?

I mean, the result is OK, but the means is incorrect.

MeAndMath

8:22 PM

@PeterTamaroff Hi,Mr. Tamaroff!

Peter Tamaroff

@MeAndMath Hello, gal.

Nimza

Good night

anon

$$\begin{array}{l} W_P(A)\xrightarrow{\Lambda}1+TA[[T]]\xrightarrow{D}TA[[T]]\xrightarrow{\pi} A^P \\ \Lambda:(x_n)_{n\in P}\mapsto\prod_{n\in P}(1-x_nT^n) \\ D=-T\frac{\partial}{\partial T}\log \\ \pi:\sum_{n\in P}w_nT^n\mapsto (w_n)_{n\in P} \\ \pi\circ D\circ \Lambda:W_P(A)\cong A^P\end{array}$$ Witt rings in a nutshell.

MeAndMath

@PeterTamaroff How are You?

anon

For $A$ of $\mathrm{Alg}_{\Bbb Q}$ anyway.

Peter Tamaroff

8:24 PM

@MeAndMath I am. And you? Are you not?

MeAndMath

@GustavoBandeira Que divertido!

@PeterTamaroff I'm good.

Peter Tamaroff

@anon Isn't this wrong?

The way the solution is obtained.

anon

It seems wrong, in that it introduces an inner limiting operation without justification.

I am writing a comment.

Peter Tamaroff

@anon Yes, thatis my point.-

anon

@PeterTamaroff I have made my comment.

Peter Tamaroff

8:35 PM

@anon Thanks. I was going to write something, but that does it. =)

@anon I had discussed that with him before, but it seems he didn't get it.

anon

I had a feeling of deja vu in fact.

Peter Tamaroff

@anon I am really strengthening up my analysis, unknown stranger.

Reading Apostol and Spivak simultaneously.

Awesome material.

MeAndMath

@GustavoBandeira What have you been studying?

Peter Tamaroff

@anon See my comment.

@anon I love the drama "which is unacceptable" produces. =D

Jonas Teuwen

My boa accidently ate the rabbit of my flatmate!! Help! What should I do??

Also, I cannot find his dog anymore!

anon

8:48 PM

Accidents happen!

Jonas Teuwen

Oh.

MeAndMath

What an accident...

Peter Tamaroff

@JonasTeuwen Get popcorn, quickly!

anon

buy an identical looking rabbit, of course

Matt

Now that's helpful.

2

MeAndMath

8:55 PM

@Matt WOW!!!

so much knowledge.

Peter Tamaroff

@Matt They are so simple ctic they need no explanation.

2

MeAndMath

Ba dum tss!

Jonas Teuwen

@Matt The definite proof Peter is gay.

3

MeAndMath

LOL!

Jonas Teuwen

@MeAndMath It's not something to laugh with man. Serious business.

Jayesh Badwaik

8:59 PM

@JonasTeuwen Woman.

MeAndMath

Yeah,I'm a girl,I can laugh.

Jayesh Badwaik

Pedro is hiding behind the huge Spivak book.

Jonas Teuwen

Oh sigh. The women have found this chat too! Men! We need a new room.

2

MeAndMath

hey!

I'm the ONLY girl here...

Peter Tamaroff

@JonasTeuwen But that page is blank! Oh, wait...

Jonas Teuwen

9:02 PM

@PeterTamaroff Read between the lines, bro.

Peter Tamaroff

@JonasTeuwen Opticians don't sell good glasses to gay people.

MeAndMath

@PeterTamaroff but I liked your glasses :P

Jonas Teuwen

Peter Tamaroff

@MeAndMath Aww

@JonasTeuwen You look like you've just powdered your nose.

Jonas Teuwen

@PeterTamaroff I have not.

Why does everybody think that? I have almost never used drugs. And no cocaine! You Argentinian... thing!

MeAndMath

9:10 PM

Maradona...

Peter Tamaroff

@JonasTeuwen The fact that you got the reference speaks by itself.

Jonas Teuwen

The what?

Peter Tamaroff

Jonas "Cokehead" Teuwen.

@JonasTeuwen The slang.

Jonas Teuwen

Everybody knows that.

It's like Banach spaces.

Peter Tamaroff

I'll grab something to eat.

@JonasTeuwen Did you know Banach was forced to feed his blood to lice?

Jonas Teuwen

9:14 PM

@Peter Everybody knows man...

Matt

@PeterTamaroff Sorry, I don't have time right now.

Peter Tamaroff

@Matt It has been settled, nevermind.

Matt

Good.

@JonasTeuwen lol

Peter Tamaroff

@Matt Have you seen this hilarious video aboud Ted Bear?

Jonas Teuwen

9:31 PM

Ted Bundy?

Peter Tamaroff

@JonasTeuwen I said Ted Bear.

MeAndMath

Ted bundy...

Jonas Teuwen

@PeterTamaroff But he looks so cuuuuute. Just like a lil' bear.

MeAndMath

girls thought so.

Peter Tamaroff

@JonasTeuwen He seems a nice person.

Jonas Teuwen

9:36 PM

Sure is. Very charismatic. Has some downsides. Might eat you - literally.

N3buchadnezzar

My name is ted bear, I like girls. Small girls. Preferably not to old, or working for the fbi.

Jonas Teuwen

@N3buchadnezzar Isn't that ...

Peter Tamaroff

►

MeAndMath

even when he was arressteed , girls sent him love letters!

N3buchadnezzar

I do not know who that is Jonas, I am also known as

Peter Tamaroff

9:39 PM

@N3buchadnezzar Oh dear.

Jonas Teuwen

@N3buchadnezzar No matter what... I will always love you bro.

No matter what they say.

It will always be our secret.

N3buchadnezzar

@JonasTeuwen Tis` is a good song bro youtube.com/watch?v=jItz-uNjoZA

2

Jonas Teuwen

One of my favs.

N3buchadnezzar

I love easy proofs they make me feel so good
I love easy proofs they make me feel so bad
When they're around they make me feel
Like I'm the only mathematician in town
I love easy proofs they make me feel so good

They don't care if I'm a one way mirror
They're not frightened by my dumb interior

They don't ask me questions
They don't want to scold me
They don't look for answers
They just want to hold me
Isn't this fun
Isn't this what life's all about
Isn't this a dream come true
Isn't this a nightmare too

Jonas Teuwen

@N3buchadnezzar We should perform the vocals for that man.

N3buchadnezzar

9:47 PM

@JonasTeuwen Yeah. And scold should be scoop

Jonas Teuwen

@N3buchadnezzar Scooped by little girls.

N3buchadnezzar

@JonasTeuwen That would feel like being kicked in the nuts right? And illegal at the same time. Woha

Jonas Teuwen

@N3buchadnezzar Yeah.

Keep Faith.