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1:29 AM
@Obliv Figures that when I ask for help I'm kicked out where I got the question.
Anyways, I've got another one. Its involving finding difference, but as I've learned its a trick. I got this far with the problem, the invisible 1 changed some of the signs. $-2d^3 + 6d - 9 + 7d^2 - 5d - 13$
Originally it was $(-2d^3 + 6d - 9) - (-7d^2 + 5d + 13)$. I got this far alone and want to confirm my thought process, so I'd like a second opinion.
 
the core principle with polynomial arithmetic is recognizing what the monomials are. in one variable d, that's powers of d, in a multivariable setting it is subtler.
the addition is defined so that you can "collect" like monomials and "add their coefficients." but none of this is well-posed without a lot of background understanding. "6a^4 b^4 +(8a^4 b^4 - 9b)" is not in anyway disqualified as an answer to an ill-formed question that just asks you to "add" those polynomials
 
Agreed. That is an ill-posed question.
 
same reason that "31 - 26/2" is a perfectly good response to "what's 31 - 26/2." specifying the form of an answer to the question is 99% of the question.
 
Were I to give a similar question to my students, the instruction would likely be something like "Simplify the following polynomial expression so that there is only one of any term of the form $Ca^m b^n$, where $C$ is a real number, and $m$ and $n$ are natural numbers."
I would need to word smith that a bit more, as it is a bit hard to grok, but I think that the general intention of the question is to get you to "combine like terms".
In other news, it is currently 77°F inside. Is it time to turn on the AC?
 
@XanderHenderson THANK YOU! Thats what I thought but wasn't sure. As soon as I finish these, I'm goin to sleep.
 
1:42 AM
@YourLordJoyBoy Again, I don't know that this is what the question writer is asking, but that is my best guess.
 
@YourLordJoyBoy Yeah so you basically distribute the minus sign. Also the first parentheses is just another implicit $1(...)$ so we just have $-2d^3+6d-9-1(-7d^2+5d+13)=-2d^3+6d-9+(-1)(-7)d^2+(-1)(5)d+(-1)(13) = -2d^3+6d-9+7d^2-5d-13)$
 
@XanderHenderson @Obliv No worries guys, I got it. :D I combined em and it ended up being $āˆ’2d^3+7d^2+dāˆ’22$
 
Actually, I would probably give the instruction "Rewrite the polynomial in standard form," where "standard form" is something that would have been discussed previously in class---roughly, write the terms in order of decreasing degree, and if two terms have the same degree, write them in lexicographical order; no two terms should contain precisely the same combination of variables, i.e. collect "like terms").
 
@XanderHenderson I believe that was in standard form, the final answer I mean. And now I'm doing a similar one, and trying to combine $9/7z with 15z$. Other than that the problem is cake.
$9/7z with 15z$
 
yeah, generally speaking, you make a problem like that unambiguous by specifying the desired form of the answer
we can all enjoy the ambiguity of "9/7z"
 
1:49 AM
@leslietownes a fraction combining with a number, each with the variable z
$9/7$
 
That clearly means $$ \frac{9}{z}\cdot 7.$$ Doi.
Hrm... or maybe $$\left\{ \frac{9}{7}, \frac{9}{z}\right\}.$$ Yeah, okay. I agree. It's ambiguous.
 
@XanderHenderson How do you do the fraction bit? And I'm trying to combine the fraction that's multiplied by z with 15z.
 
@YourLordJoyBoy I think that, perhaps, the joke has flown past you a bit too quickly. Something that you should keep in mind is that Xander lies.
 
@XanderHenderson To be fair, any joke'll pass me quick when I'm this tired. XD I'm tempted to dub you Usopp now with the lying habit though.
 
@YourLordJoyBoy Sadly, your joke flew over my head.
Is Usopp some gen alpha thing?
 
1:56 AM
@XanderHenderson Consider it vengeance XD
I'll probably explain it in time
Unless someone else gets it and decides to.
 
Google says its some shonen BS.
 
@XanderHenderson Yes, its a character who is always telling tall tales. XD
 
(The question is, how many otaku / weebs do I piss off by calling One Piece 'some shonen BS'?)
 
@XanderHenderson Not me since I could care less who hates it XD
$$\frac{9}{7}{z} + {15}{z}$$ Wonder if I did this right
$$\frac{9}{7}{z} + {15}{z}$$
ABSOLUTELY SCREWED THAT UP! :o
FTR, only adding a star to those two messages.
 
@YourLordJoyBoy I don't hate it. I simply have no feelings toward it at all.
I bounce off of most shonen BS pretty hard.
 
2:05 AM
In other words, @XanderHenderson just no care.
For me however, it heavily impacted meh life during hard times.
And you're still Usopp to me XD
But seriously its one of those things, you're going through crap times irl and something crazy pops up that proves to be a fantastic escape from the reality bs in your life.
 
2:20 AM
@XanderHenderson I don't care about One Piece, but I'll take issue on general grounds of reductiveness
 
3:08 AM
@Thorgott Good. That was the reaction I was hoping for. :D
 
me: modifies someone else's Tikz code to make a mass spectrometer
result:
 
@Semiclassical I might try to learn Tikz someday. But I learned pstricks such a long time ago, and Tikz looks so very annoyingly not at all the same.
 
That looks like a butt.
 
i'd agree, except for the shaft going upward. but that makes it worse
 
3:11 AM
Oh, sure. It could be a dick'n'balls.
I see that, now that you mention it.
Maybe it's both things!
Right. I need to go to bed. It is so late.
It is after EIGHT PM!
 
 
2 hours later…
5:15 AM
when people say the killing form is "ad" invariant, do they mean little or big adjoint?
concretely, with matrices little ad is the commutator over lie algebra $[X, -]$ and big adjoint is lie group conjugation over lie algebra $g(-)g^{-1}$
 
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