hello. i am wondering if i am misinterpreting (4.70). For the $n=7$ case, I am getting that $\sum_i n_i^2 \neq 1$

I have defined n0 to n7 above and then the final line at the bottom is computing the sum of squares

the only thing i can think of is maybe all $n_i$ s.t. $2 \leq i \leq n$ should have a $\cos$ as the first trig function

because there is certainly no way to obtain $1$ out of the way I interpreted the table

bleb i think that's it...

god

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