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11:05 PM
Could someone who knows inorganic (better than I do, at any rate, which probably qualifies just about anyone) take a look at this answer? chemistry.stackexchange.com/questions/472/… My intuition when I asked the question was that it was more complicated than the answer implies due to the formation of the complex.
I'm happy to have an answer to it finally, but I can't really evaluate whether it actually answers the question.
 

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