@halirutan The definition is being typeset as a single-column GridBox with the width of the column being set to Scaled[0.999]. In this context, Scaled is going to pick up its width from the window's width. Since there are two of them in this expression, it's always going to double the width. Some open questions here...
* Why isn't a line-break happening between the two GridBoxes? Hmm...looks like it could be a bug to me.
* Why is the column set to that width in the first place? I'm pretty sure there's a good reason for it, but I don't know what it is off the top of my head.
@halirutan , @JohnFultz: thanks for the analysis, and the report. I came around this bug by trying to put a function definition in a PlotLabel, like Plot[x, {x, 0, 1}, PlotLabel -> Definition@f], which leaves the label blank.
ToString and InputForm works, but not TraditionalForm on this one.
people really should be closing questions like this one... there are several such questions
Just because the original is "How do I convert A to a list" and someone asks "How do I convert B to a list" doesn't mean it shouldn't be closed as a dupe/TL when the answer is use Apply or use foo -> List
@rm-rf Believe it or not I cannot seem to find a good, simple duplicate for closing. You seem to do much better with searching than do I; do you have one in mind?
@Mr.Wizard a bit busy now and not at a comfortable computer, but I remember this mathematica.stackexchange.com/q/10833/5 was closed as TL because apply is basic. I'll getback on this later when I'm free
This is a spinoff of this question
Defining
$$f_0(x) = x$$
$$f_n(x) = \log(f_{(n-1)} (x)) \space (\forall n>0)$$
and
$$a_0 = 1$$
$$a_{n+1} = (n+1)^{a_n} \space (\forall n>0)$$
How to calculate
$$\lim_{n \to \infty } f_n(a_n) $$
(an "experiment" here, but (beware) I think WolframAlpha...
I finally saw the problem with my "injector pattern" that you tried to point out months ago. I don't have a good grasp of the automatic scoping protection I guess. I think I have another method that is unaffected, but I'd like it, if you're willing, if you would lay out your understanding of the mechanism.
I have searched stackoverflow (and comparable pages) for quite a while now (got redirected from there to this specialized stack), and I surrender. I am trying to evaluate an expression that is small in the end numerically.
Example:
Log[Log[Log[6^5^4^3^2^1]]]=12.9525...
WolframAlpha has no pro...
@halirutan I've never used it, but someone (I presume rm -rf) gave me access to it so that I could move attachments to a more secure place. I assumed this was an easy option, but if have to install all kinds of programs and have to familiarize myself with all kinds of complex procedures this isn't really an attractive option.
@SjoerdC.deVries It's still a versioning system. It assumes that either someone wants to only download all or parts of the repository for compilation and if someone wants to upload files, he is developer who should have all/parts of the source-tree on his computer.
@SjoerdC.deVries I don't upload by committing because I'm not sure how to manage it with so many users (each will have to pull/fetch regularly and keep files even if they don't need it). If you go to the downloads page, there's a link to upload
@rm-rf @halirutan I already used the picture trick, a process that takes less than a second. I'm off to bed now, but feel free to remove the piece of code and replace it with a link to GitHub.
A couple of years ago I was in an email conversation about this topic with Jeff Bryant, a WRI employee. He was not directly responsible for AstronomicalData, but he told me that Mathematica did not correct for atmospheric refraction. Good to know, as the refraction at the horizon is about the sam...
This is a spinoff of this question
Defining
$$f_0(x) = x$$
$$f_n(x) = \log(f_{(n-1)} (x)) \space (\forall n>0)$$
and
$$a_0 = 1$$
$$a_{n+1} = (n+1)^{a_n} \space (\forall n>0)$$
How to calculate
$$\lim_{n \to \infty } f_n(a_n) $$
(an "experiment" here, but (beware) I think WolframAlpha...
I have searched stackoverflow (and comparable pages) for quite a while now (got redirected from there to this specialized stack), and I surrender. I am trying to evaluate an expression that is small in the end numerically.
Example:
Log[Log[Log[6^5^4^3^2^1]]]=12.9525...
WolframAlpha has no pro...
