1:50 PM
3
Any ideas on how to calculate the limit of $(e^x -1)/{x}$ as $x$ goes to zero without applying L'Hôpital's rule?
11
I was messing around with the definition of the derivative, trying to work out the formulas for the common functions using limits. I hit a roadblock, however, while trying to find the derivative of $e^x$. The process went something like this: $$\begin{align} (e^x)' &= \lim_{h \to 0} \frac{e^{x+h...
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