10:11 AM
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How do I compute this integral ? $$I=\int_{0}^{1}\ln{\left(\ln{\left(\dfrac{1}{x}+\sqrt{\dfrac{1}{x^2}-1}\right)}\right)}dx$$ In the math chatroom someone suggests setting $x=\operatorname{sech}(t)$ and that the result immediately follows. I don't agree with it because \dfrac{1}{x...

This question was closed as off-topic, now it has 4 votes to reopen.
But in the meantime also a duplicate has been suggested: